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2 years ago

Compare How does the horse's average speed from 60 s to 120 s compare to its average speed from 120 s to 180 s?

Chemistry

1 answer:

Juli2301 [7.4K]2 years ago

5 0

Answer:

Explanation:

To compare the average speed, we would need some parameters which you clearly didn't state in your question. However, permit me to manufacture some from thin air.

The formula for average speed is given as

Speed = distance / time

From the question, we have the time, but not the distance moved by the horse. Now, assuming the horse moves a distance of 60 meters, then we can say,

Speed = 60 / 60

Where the difference between the two time, t = 120 - 60 = 180 - 120 = 60

So, from my hypothesized example, the average speed of the horse is 1 m/s

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Consider the following reactions and their respective equilibrium constants: NO(g)+12Br2(g)⇌NOBr(g)Kp=5.3 2NO(g)⇌N2(g)+O2(g)Kp=2

maxonik [38]

Answer:

Equilibrium constant of the given reaction is $1.3\times 10^{-29}$

Explanation:

$NO+\frac{1}{2}Br_{2}\rightleftharpoons NOBr$ .... $(K_{p})_{1}=5.3$

$2NO\rightleftharpoons N_{2}+O_{2}$ .... $(K_{p})_{2}=2.1\times 10^{30}$

The given reaction can be written as summation of the following reaction-

$2NO+Br_{2}\rightleftharpoons 2NOBr$

$N_{2}+O_{2}\rightleftharpoons 2NO$

......................................................................................

$N_{2}+O_{2}+Br_{2}\rightleftharpoons 2NOBr$

Equilibrium constant of this reaction is given as-

$\frac{[NOBr]^{2}}{[N_{2}][O_{2}][Br_{2}]}$

$=(\frac{[NOBr]}{[NO][Br_{2}]^{\frac{1}{2}}})^{2}(\frac{[NO]^{2}}{[N_{2}][O_{2}]})$

$=\frac{(K_{p})_{1}^{2}}{(K_{p})_{2}}$

$=\frac{(5.3)^{2}}{2.1\times 10^{30}}=1.3\times 10^{-29}$

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3 years ago

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Which elements can form acidic compounds?

pashok25 [27]

Sodium and magnesium oxides are alkaline. Aluminium oxides are amphoteric (reacting both as a base or acid). Silicon, phosphorus, sulfur, and chlorine oxides are acidic. Some non-metal oxides, such as nitrous oxide (N2O) and carbon monoxide (CO), do not display any acid/base characteristics.

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3 years ago

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calculate the volume occupied by 10g of propane gas, under normal conditions of temperature and pressure

andriy [413]

Answer:

5.5 L

Explanation:

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10 g ÷ 44 g/mol = 0.23 mol

Then we use the PV=nRT formula, where:

P = 1 atm & T = 293 K (This are normal conditions of T and P)

n = 0.23 mol

R = 0.082 atm·L·mol⁻¹·K⁻¹

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3 years ago

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Dmitriy789 [7]

Answer:

Explanation:

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2 years ago

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Whitepunk [10]

Answer:

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Explanation:

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