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Sedaia [141]
3 years ago
10

Convert 9.83 m/s with a radius of 0.85 m to rotations per minute (rpm)

Physics
1 answer:
marissa [1.9K]3 years ago
3 0

Answer: Conversion of 9.83 m/s with a radius of 0.85 m into rotations per minute (rpm) is 99.25 m^{-1}.

Explanation:

Given: Speed = 9.83 m/s

Convert m/s into m/minute as follows.

1 min = 60 sec\\9.83 m/s = 9.83 m/s \times \frac{60 s}{1 min}\\= 529.8 m/min

Radius = 0.85 m

Now, rotations take place in circular motion. So, the circumference of a circle is 2 \pi r.

Therefore, circumference is calculated as follows.

Circumference = 2 \times pi \times r\\= 2 \times 3.14 \times 0.85 m\\= 5.338 m

Formula used to calculate rotations per minute (rpm) are as follows.

rpm = \frac{speed (in meter per minute)}{circumference}\\= \frac{529.8 m/min}{5.338 m}\\= 99.25 m^{-1}

Thus, we can conclude that conversion of 9.83 m/s with a radius of 0.85 m into rotations per minute (rpm) is 99.25 m^{-1}.

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Answer:

The necessary information is if the forces acting on the block are in equilibrium

The coefficient of friction is 0.577

Explanation:

Where the forces acting on the object are in equilibrium, we have;

At constant velocity, the net force acting on the particle = 0

However, the frictional force is then given as

F = mg sinθ

Where:

m = Mass of the block

g = Acceleration due to gravity and

θ = Angle of inclination of the slope

F = 5×9.81×sin 30 = 24.525 N

Therefore, the coefficient of friction is given as

24.525 N = μ×m×g × cos θ = μ × 5 × 9.81 × cos 30 = μ × 42.479

μ × 42.479 N= 24.525 N

∴ μ = 24.525 N ÷ 42.479 N = 0.577

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I hope it's helpful!!

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Explanation:

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