All categories

3 years ago

Which has more momentum?

1 answer:

3 0

The 7.0-kilogram bowling ball has a momentum of 42kgm/s whike the 0.064-kilogram golf ball has a momentum of 3.84kgm/s

Bowling ball is your answer

You might be interested in

Which statement correctly describes these electric field lines

JulijaS [17]

Answer:

Explanation:

the correct answer is C please follow me

8 0

3 years ago

Read 2 more answers

ARRANGE THE STEPS IN ORDER TO DESCRIBE WHAT HAPPENS TO A GAS WHEN IT COOLS

vredina [299]

What happens to has when it cools is ...
Step 1) They will start to form liquids, like condensation.
Step 2) As liquids cool, they will turn into solids.
Step 3) As solids cool, they become more stable and solid.

3 0

3 years ago

How much energy or stopping power is needed to bring a car to a stop from 100 mph?

Fed [463]

I think 100 mph pushing the car the opposite direction

3 0

3 years ago

Glycerin (C3H8O3) is a nonvolatile liquid. What is the vapor pressure of a solution made by adding 154 g of glycerin to 316 mL o

garri49 [273]

Answer:

$P_{sol}=50.4\ mm.Hg$

Explanation:

According to given:

molecular mass of glycerin, $M_g=3\times 12+8+3\times 16=92\ g.mol^{-1}$

molecular mass of water, $M_w=2+16=18\ g.mol^{-1}$

∵Density of water is $0.992\ g.cm^{-3}= 0.992\ g.mL^{-1}$

∴mass of water in 316 mL, $m_w=316\times 0.992=313.5 g$

mass of glycerin, $m_g=154\ g$

pressure of mixture, $P_x=55.32\ torr= 55.32\ mm.Hg$

temperature of mixture, $T_x=40^{\circ}C$

Upon the formation of solution the vapour pressure will be reduced since we have one component of solution as non-volatile.

moles of water in the given quantity:

$n_w=\frac{m_w}{M_w}$

$n_w=\frac{313.5}{18}$

$n_w=17.42 moles$

moles of glycerin in the given quantity:

$n_g=\frac{m_g}{M_g}$

$n_g=\frac{154}{92}$

$n_g=1.674 moles$

Now the mole fraction of water:

$X_w=\frac{n_w}{n_w+n_g}$

$X_w=\frac{17.42}{17.42+1.674}$

$X_w=0.912$

Since glycerin is non-volatile in nature so the vapor pressure of the resulting solution will be due to water only.

$\therefore P_{sol}=X_w\times P_x$

$\therefore P_{sol}=0.912\times 55.32$

$P_{sol}=50.4\ mm.Hg$

7 0

3 years ago

THE RIGHT ANSWER WILL RECEIVE A BRAINLESS AND POINTS AND THANKS!!! THE RIGHT ANSWER WILL RECEIVE A BRAINLESS AND POINTS AND THAN

timurjin [86]

Answer:

$f_{o}$ = 391.67 Hz

Explanation:

The sound of lowest frequency which is produced by a vibrating sting is called its fundamental frequency ( $f_{o}$ ).

The For a vibrating string, the fundamental frequency ( $f_{o}$ ) can be determined by:

$f_{o}$ = $\frac{v}{2L}$

Where v is the speed of waves of the string, and L is the length of the string.

L = 42.0 cm = 0.42 m

v = 329 m/s

$f_{o}$ = $\frac{329}{2*0.42}$

= $\frac{329}{0.84}$

$f_{o}$ = 391.6667 Hz

The fundamental frequency of the string is 391.67 Hz.

3 0

3 years ago