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EleoNora [17]
3 years ago
13

Which requires more energy: lifting a 50 kg sack vertically 2 meters or lifting a 25 kg sack vertically 4 meters?

Physics
2 answers:
gtnhenbr [62]3 years ago
5 0

Answer: C) both require the same amount of work

Explanation:

If you think about 25 is half of 50 and 2 is half of 4 and 50 times 2 =100 and

25 times 4 =100

elena-s [515]3 years ago
3 0

Answer:

c. Both require the same amount of work

Explanation:

GPE = mgh

50 * 10 * 2 = 1000 J

25 * 10 * 4 = 1000 J

Therefore, both are same and require the same amount of work.

Thenk and mark me brainliest :)

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Two identical parallel plate capacitors A and B connected to a battery of V volts w/ the switch S closed. The switch is now open
Basile [38]
The electrostatic energy stored in a capacitor with capacitance C_0, with a voltage difference V applied to it, and without dielectric, is given by
U_0 =  \frac{1}{2} C_0 V^2
Now let's assume we fill the space between the two plates of the capacitor with a dielectric with constant k. The new capacitance of the capacitor is
C_k = k C_0
So, the energy stored now is
U_k =  \frac{1}{2}C_k V^2= \frac{1}{2}kC_0 V^2

Therefore, the ratio between the energies stored in the capacitor before and after the introduction of the dielectric is
\frac{U_k}{U_0}= \frac{ \frac{1}{2}kC_0 V^2 }{ \frac{1}{2} C_0 V^2}=  k
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3 years ago
Does specific heat of a substance depend on its temperature?​
lara [203]

Answer:

temperature

Explanation:

In general, the specific heat also depends on the temperature. The table below lists representative values of specific heat for various substances. Except for gases, the temperature and volume dependence of the specific heat of most substances is weak.

4 0
3 years ago
Which energy conversion takes place when a solar cell is used to light a street lamp?
allsm [11]

Answer:

the answer is for the question is B

8 0
3 years ago
A charged wire of negligible thickness has length 2L units and has a linear charge density λ. Consider the electric field E-vect
Stels [109]

Answer:

E=2K\lambda d\dfrac{L }{d^2\sqrt{L^2+d^2}}

Explanation:

Given that

Length= 2L

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E=2K\int_{0}^{L}\dfrac{\lambda }{r^2}dx\ sin\theta

sin\theta =\dfrac{d}{\sqrt{d^2+x^2}}

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So

E=2K\lambda d\int_{0}^{L}\dfrac{dx }{(x^2+d^2)^{\frac{3}{2}}}

Now by integrating above equation

E=2K\lambda d\dfrac{L }{d^2\sqrt{L^2+d^2}}

4 0
3 years ago
What does the negative sign in F = –kx mean?
Andru [333]
The force is opposite to the displacement
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