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EleoNora [17]
3 years ago
13

Which requires more energy: lifting a 50 kg sack vertically 2 meters or lifting a 25 kg sack vertically 4 meters?

Physics
2 answers:
gtnhenbr [62]3 years ago
5 0

Answer: C) both require the same amount of work

Explanation:

If you think about 25 is half of 50 and 2 is half of 4 and 50 times 2 =100 and

25 times 4 =100

elena-s [515]3 years ago
3 0

Answer:

c. Both require the same amount of work

Explanation:

GPE = mgh

50 * 10 * 2 = 1000 J

25 * 10 * 4 = 1000 J

Therefore, both are same and require the same amount of work.

Thenk and mark me brainliest :)

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Vilka [71]

Answer:

Kaboom daddy

Explanation:

8 0
2 years ago
Read 2 more answers
What is the change in potential energy of a 2.00 nC test charge, Uelectric, b - Uelectric, a, as it is moved from point a at x
lyudmila [28]

The question is incomplete. Here is the complete question.

A uniform electric field of 2kN/C points in the +x-direction.

(a) What is the change in potential energy of a +2.00nC test charge, U_{electric,b} - U_{electric,a} as it is moved from point a at x = -30.0 cm to point b at x = +50.0 cm?

(b) The same test charge is released from rest at point a. What is the kinetic energy when it passes through point b?

(c) If a negative charge instead of a positive charge were used in this problem, qualitatively, how would your answers change?

Answer: (a) ΔU = 3.2×10^{-6} J

(b) KE = 2×10^{-6} J

Explanation: <u>Potential</u> <u>Energy</u> (U) is the amount of work done due to its position or condition and its unit is Joule (J). <u>Kinetic</u> <u>Energy</u> (KE) is the ability to do work by virtue of velocity and the unit is also (J). <u>Mechanical</u> <u>Energy</u> is the sum of Potential and Kinetic Energies of a system.

(a) Related to electricity, Potential Energy can be calculated as:

ΔU = Eqd

where E is the electric field (in N/C);

q is the charge (in C);

d is the distance between plaques (in m);

For a at x = - 30cm and b at x = 50 cm:

E = 2×10^{3} N/C

q = 2×10^{-9} C

d = 50 - (-30) = 80×10^{-2} = 8×10^{-1}m

ΔU = U_{electric,b} - U_{electric,a} = Eqd

U_{electric,b} - U_{electric,a} = 2×10^{3} .  2×10^{-9} . 8×10^{-1}

ΔU = 3.2×10^{-6} J

(b) Mechanical Energy is constant, so:

KE_{i} + U_{i} = KE_{f} + U_{f}

Since the initial position is zero and there is no initial kinetic energy:

KE_{f} = - U{f}

KE_{f} = - (2×10^{3}. 2×10^{-9} . 5×10^{-1})

KE_{f} = - 2.10^{-6} J

(c) If the charge is negative, electric field does positive work, which diminishes the potential energy. The charge flows from the negative side towards the positive side and stays, not doing anything.

8 0
3 years ago
two vectors have a magnitude of 2.5km and 6.5 km . Predict the maximum and minimum magnitudes of their resultant vector
agasfer [191]

The maximum magnitude of their resultant vector is when the two vectors are parallel and in the same direction, so they lie on the same axis. In this case, the magnitude of their resultant vector is simply the sum of the two magnitudes:

R=2.5 km+6.5 km=9.0 km


The minimum magnitude of their resultant vector is when the two vectors are parallel but in opposite direction. In this case, the magnitude of their resultant vectors is just the difference between the two magnitudes:

R=6.5 km-2.5 km=4.0 km

8 0
3 years ago
As viewed from our location, the stars of the Big Dipper canbe connected with imaginary lines to form the shape of a pot with ac
jasenka [17]

Answer: California

Explanation:

The Big Dipper has eight stars in it. Seven are visible at a glance, while the eighth is a visible double star that is just detectable with the naked eye in an area with clear "seeing" and with good vision.

To first observe an easily recognizable change in the shape formed by these stars (to an observer without a telescope), someone can look high in the sky toward the northeast at a certain time of the year and you can't miss the Big Dipper at around 8 p.m from mid-northern latitudes which is California

5 0
3 years ago
A rectangular box of lines and an extra vertical line near the right end of the box has circles with X's in them on the right si
irakobra [83]

Light bulbs 1, 2, and 4 will continue to shine when Linh switches off bulb 3.

<h3>What exactly is a circuit?</h3>

The battery-powered electrical circuit where a voltage differential is generated across a capacitor, a resistor, or an inductor.

As soon as Linh cuts the middle branch, the bulbs in positions 1, 2, and 4 will function as a resistor in a series circuit. Except for resistor number 3, the current through the other resistors will be constant.

In conclusion, if Linh switches off Bulb 3, only Bulbs 1, 2, and 4 will still be on.

Understand the basics of circuits at

brainly.com/question/12608516

#SPJ1

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