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Andre45 [30]
3 years ago
9

Identify at least one example each of absorption, transmission, reflection, and refraction of waves in this photograph.

Physics
1 answer:
hoa [83]3 years ago
4 0

Answer:

Explanation:

example of absorption=sunlight landing on a face is mostly absorbed, warming the skin.                                                                                                                   example of transmission=light passing through a glass window continues with over 95% of its energy                                                                                         example of reflection=reflection of light, sound and water waves.               example of refraction=a bending of the sun's rays as they enter raindrops, forming a rainbow.

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Two 25 kg children are sitting on a merry-go-round that is rotating at 0.10 rad/s. if one child is 1.0 m from the center and the
Grace [21]
The angular speed of the merry-go-round is
ω = 0.10 rad/s

The angular moment of inertia of a mass, m, at a radius, r, from the center of the wheel is
I = mr²

Therefore, the angular moment of inertia for the children are
I₁ = (25 kg)*(1.0 m)² = 25 kg-m²
I₂ = (25 kg)*(1.5 m)² = 56.25 kg-m²

The combined angular momentum is
ω(I₁ + I₂) = (0.10 rad/s)*(25 + 56.25 kg-m²)
               = 8.125 (kg-m²)/s

Answer: 8.125 (kg-m²)/s
8 0
4 years ago
A 0.50-kg block attached to an ideal spring with a spring constant of 80 N/m oscillates on a horizontal frictionless surface. Th
wolverine [178]

Answer:

Explanation:

easy way

when system is all kinetic energy, velocity is at a maximum

E = ½mv²

v = √(2E/m) = √(2(25)/0.5) = √100 = 10 m/s

harder way

ω = √(k/m) = √(80/0.5) = √160 rad/s

When the system is entirely spring potential, the amplitude A is

E = ½kA²

A = √(2E/k) = √(2(25)/80) = 0.790569... = 0.79 m

maximum velocity is ωΑ = 0.79√160 = 10 m/s

6 0
3 years ago
The moon's illumination changes in a periodic way that can be modeled by a trigonometric function. On the night of a full moon,
kupik [55]

Answer:

L(t) = 0.125 (cos (\frac{\pi}{14.765}(t+7)) + 0.125

Explanation:

The expression for the  trigonometric function is :

L(t) = A (cos (B(t - C)))+ D   ----- equation (1)

where ;

A = \frac{max-min}{2}

A = \frac{0.25-0}{2}

A = 0.125

D = \frac{0+.025}{2}

D = 0.125

Period of the lunar cycle = 29.53

Then;

\frac{2 \pi}{B}  = 29.53

29.53 \ \ B = 2 \pi

B = \frac{2 \pi}{29.53}

B = \frac{\pi}{29.53}

Also; we known that December 25 is 7 days before January 1.

Then L(-7) = 0.025

Plugging all the values into trigonometric function ; we have:

0.125 ( cos ( \frac{\pi}{14.765}((-7)-C)))+0.125 = 0.25 \\ \\ \\  ( cos ( \frac{\pi}{14.765}((-7)-C))) = \frac{0.25-0.125}{0.125}

( cos ( \frac{\pi}{14.765}((-7)-C))) = 1

( \frac{\pi}{14.765}((-7)-C))= cos^{-1} (1)

}((-7)-C))=0

C= -7

L(t) = 0.125 (cos (\frac{\pi}{14.765}(t-(-7))) + 0.125

L(t) = 0.125 (cos (\frac{\pi}{14.765}(t+7)) + 0.125

7 0
3 years ago
Bromine is a liquid at room temperature. The volume of a sample of bromine is measured in a 50 beaker and a 100 ml beaker. How w
Stells [14]

Answer:

The comparisons are;

The height of the bromine in the 50 ml beaker will be twice that of the 100 ml beaker

The measurement of the volume with the 50 ml beaker will be more accurate than the measurement taken with the 100 ml beaker, because the differences in the height of the bromine in the 50 ml beaker is more obvious than the differences measured with the 100 ml beaker.

The actual volume of bromine in both beakers will be equivalent

Explanation:

The properties of a liquid are;

1) The volume of a liquid is relatively fixed at conditions that are suitable for it to remain in the liquid state compared to the volume occupied by a gas

2) A liquid will assume the shape of a container in which it is placed

3) The surface of a liquid in a container is flat due in order that the attractive forces between the molecules of the liquid at the surface and inside the body of the liquid should be in equilibrium

Therefore, given that the volume of the Bromine is measured in 50 ml beaker and a 100 ml beaker, there will be differences in the measured height of the same volume of bromine in each beaker.

5 0
3 years ago
Determine the electric field (in N/C) required to give the maximum possible deviation angle. (Enter the magnitude.)
Zigmanuir [339]

Answer:

Maximum angle = 3.43⁰

Explanation:

Say that you are given the following information:

vertical distance between the charge plate = 0.03 m

length of the plate = 0.5 m

velocity of the electrons = 5 × 10⁶ ms⁻¹

the maximum angle is given by the formula:

tan\theta _{max}  = \frac{d}{l}

where d = vertical distance between the charge plate

l = length of the plate

substituting the values l and d gives:

tan\theta _{max} = \frac{0.03}{0.5}

maximum angle, \theta _{max}  = \frac{0.03}{0.5}

                                      \theta _{max} = tan^{-1} (\frac{0.03}{0.5} )

                                               =  3.43⁰

3 0
4 years ago
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