Nearly all physics problems will use the unit m/s squared. Why are the seconds squared?
1 answer:
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Answer:
a) The distance of spectator A to the player is 79.2 m
b) The distance of spectator B to the player is 43.9 m
c) The distance between the two spectators is 90.6 m
Explanation:
a) Knowing the time it takes the sound to reach both spectators, we can calculate their position relative to the player, using this equation:
x = v * t
where:
x = position of the spectators
v = speed of sound
t = time
Then, the position for spectator A relative to the player is:
x = 343 m/s * 0.231 s = 79.2 m
b)For spectator B:
x = 343 m/s * 0.128 s
x = 43.9 m
The distance of spectator A and B to the player is 79.2 m and 43.9 m respectively.
c) To calculate the distance between the spectators, please see the attached figure. Notice that the distance between the spectators is the hypotenuse of the triangle formed by the sightline of both. We already know the longitude of the two sides. Then, using Pythagoras theorem:
(Distance AB)² = A² + B²
(Distance AB)² = (79.2 m)² + (43.9 m)²
Distance AB = 90. 6 m
Answer:
T_2= 234.37 K
Explanation:
According to Claperyon, we know that
P_1= Atmospheric pressure 760 mm Hg
P_2 = pressure at the bottom of the column
= 10×10^3 mm of Hg+ 760 mm of Hg
= 10760 mm of Hg
now,
P_2-P_1= 10760-760= 10^4 mm
P_2-P_1 ( in pascals) = 10^4× 133.322= 1333220 mm
the enthalpy of fusion (ΔH-fus) of mercury is 2.292 KJ/mol
use the above equation to calculate ΔT as follows
therefore, T_2= 234.37 K