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2 years ago

How do plate tectonics affect mountains?

Chemistry

2 answers:

bearhunter [10]2 years ago

5 0

Answer:

C. Plate tectonic collisions can create mountains.

Stels [109]2 years ago

4 0

Answer:

They can make them larger

Explanation:

They go up under a mountain and then the mountains rise up

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Marissa blows up balloons for a party. She decides how big or small to make each balloon. Why does the air she blows into each b

Oxana [17]

Air is it gas so it fills its container, the balloon, completely.

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3 years ago

A student listed three ways to predict if a bond is ionic.

natka813 [3]

1 and 3 only because metal are easily to loss electron while non metal are difficult to loss electron that's why it called heavy elements.

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2 years ago

An interplanetary probe returns to Earth with soil samples. The atoms in the sample are sorted by their number of protons. A new

Leya [2.2K]

Answer is: the average atomic mass is 232.

ω₁ = 20% ÷ 100%.

ω₁ = 0.20.

ω₂ = 80% ÷ 100%.

ω₂ = 0.80.

Ar₁ = 120 (number of protons) + 120 (number of neutrons).

Ar₁ = 240.

Ar₂ = 120 + 110 .

Ar₂ = 230.

Average atomic mass of atoms of bolognium =

Ar₁ · ω₁ + Ar₂ · ω₂.

Average atomic mass of atoms of bolognium = 240 · 0.2 + 230 · 0.8.

Average atomic mass of atoms of bolognium = 48 + 184.

Average atomic mass of atoms of bolognium = 232.

4 0

3 years ago

In solid NaCl, the equilibrium separation between neighboring Na+ and Cl- ions is 0.283 nm. Calculate the coulombic energy betwe

const2013 [10]

Explanation:

It is given that r = 0.283 nm. As 1 nm = $10^{-9} m$ .

Hence, 0.283 nm = $0.283 \times 10^{-9} m$

Formula for coulombic energy is as follows.

$U_{coulomb} = -1.748 \frac{e^{2}}{4 \pi \epsilon_{o} r}$

where, e = $1.6 \times 10^{-19}$ C

$\epsilon_{o}$ = $8.85 \times 10^{-12}$

$U_{coulomb} = -1.748 \frac{(1.6 \times 10^{-19}^{2}}{4 \times 3.14 \times 8.85 \times 10^{-12} \times 0.283 \times 10^{-9}}$

= $1.423 \times 10^{-18} J$

As 1 eV = $1.6 \times 10^{-19} J$

So, 1 J = $\frac{1 eV}{1.6 \times 10^{-19}}$

Hence, U = $\frac{1.423 \times 10^{-18} J}{1.6 \times 10^{-19} J}$

= 8.9 eV

Also, 1 J = $\frac{10^{-3} kJ}{6.022 \times 10^{23}mol}$

= $1.67 \times 10^{-27}$ kJ/mol

Therefore, U = $1.423 \times 10^{-18} J \times 1.67 \times 10^{-27}$ kJ/mol

= $2.37 \times 10^{-45} kJ/mol$

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3 years ago

A cheeseburger from a fast food restaurant contains 19 g of fat, 20 g of carbohydrate, and 28 g of protein. how many kcal of ene

Burka [1]

I believe the answer is D

3 0

3 years ago