All categories

3 years ago

If a person had the values for an objects density and volume, what value can be calculated

Chemistry

2 answers:

zavuch27 [327]3 years ago

5 0

Hello there! With the values of density and volume, you would be able to find the object's mass.

Density is found by dividing the mass by the volume, so you could place in the values of the density and the volume to get the mass.

For example:

500 = mass/10

The 500 being density and 100 being volume. You would use simple math rules and multiply 10 by 500, and you'd get 5000, therefore using the density and volume values and giving you the mass.

I hope I could help you and have a great day!

Nady [450]3 years ago

3 0

Answer:

Clearly, you can assess the mass of the object.

Explanation:

Density,

Mass

Volume

. And for chemists,

typically has the units

⋅

−

⋅

−

Thus, if you had values for

and

volume

, you could assess the mass of the object by taking the product:

Mass

volume

density

Such a product gives units of grams as required, because

⋅

−

grams

Explanation:

You might be interested in

Which one of the following is not equal to 100 meters

Katena32 [7]

Where is the link can’t do any work without it

7 0

3 years ago

If water were a non-polar Molecule

JulijaS [17]

Answer:

Water would not be able to transport nutrients -‐-‐ in plants, or in our bodies -‐-‐ nor to dissolve and transport waste products out of our bodies. ... Cohesiveness, adhesiveness, and surface tension: would decrease because without the +/-‐ polarity, water would not form hydrogen bonds between H20 molecules.

8 0

3 years ago

Using the equations 2 Sr(s) + O₂ (g) → 2 SrO (s) ∆H° = -1184 kJ/mol SrO (s) + CO₂ (g) → SrCO₃ (s) ∆H° = -234 kJ/mol CO₂ (g) → C(

kkurt [141]

Answer: The $\Delta H^o_{rxn}$ for the reaction is 72 kJ.

Explanation:

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

$2SrCO_3(s)\rightarrow 2Sr(s)+2C(s)+3O_2(g)$ $\Delta H^o_{rxn}=?$

The intermediate balanced chemical reaction are:

(1) $2Sr(s)+O_2(g)\rightarrow 2SrO(s)$ $\Delta H_1=-1184kJ$

(2) $SrO(s)+CO_2(g)\rightarrow SrCO_3(s)$ $\Delta H_2=-234kJ$ ( × 2)

(3) $CO_2(g)\rightarrow C(s)+O_2(g)$ $\Delta H_3=394kJ$ ( × 2)

The expression for enthalpy of the reaction follows:

$\Delta H^o_{rxn}=[1\times (\Delta H_1)]+[2\times (-\Delta H_2)]+[2\times (\Delta H_3)]$

Putting values in above equation, we get:

$\Delta H^o_{rxn}=[(1\times (-1184))+(2\times -(-234))+(2\times (394))]=72kJ$

Hence, the $\Delta H^o_{rxn}$ for the reaction is 72 kJ.

4 0

3 years ago

Consider an ideal gas enclosed in a 1.00 L container at an internal pressure of 14.0 atm. Calculate the work, w , if the gas exp

Vaselesa [24]

Answer:ryhrthyhytnthnthnthnthntnt

Explanation:

6 0

3 years ago

Write the formulas of the three singly chlorinated isomers formed when 2,2-dimethylbutane reacts with Cl2 in the presence of lig

Tems11 [23]

The molecule with same molecular formula but different arrangement of atoms is said to be an isomer.

When 2,2-dimethylbutane reacts with chlorine in the presence of light gives three isomers that is $CH_{3}C(CH_{3})_{2}CHClCH_{3}$ (3-chloro-2,2-dimethylbutane), $ClCH_{2}C(CH_{3})_{2}CH_{2}CH_{3}$ (1-chloro-2,2-dimethylbutane) and $ClCH_{2}CH_{2}C(CH_{3})_{2}CH_{3}$ (1-chloro-3,3-dimethylbutane).

In above case, the molecular formula of all isomers are same i.e. $C_{6}H_{13}Cl$ but chlorine is arranged in different positions of carbon. Thus, results isomers.

The reaction is shown in the image.

3 0

3 years ago