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Brrunno [24]
3 years ago
6

What is the hypotenuse of a right triangle that has legs of 12x and 9x

Mathematics
1 answer:
AURORKA [14]3 years ago
5 0

Answer: 15

Step-by-step explanation:

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I need help ASAP!!!!!!!!!!!!
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Answer:

I hope this helps!

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Which of the numbers listed below are solutions to the equation? Check all
8_murik_8 [283]

Answer:

The answer is 25 and -25 :)

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3 years ago
Find the slope of the line that is parallel to the line y=2x+5<br> ​ <br> ​ m=
OlgaM077 [116]
M=2
The slope intercept form is y=Mx+b,where m is the slope and b is the y intercept y=Mx+b

Using the slope intercept form the slope is 2 m=2

All lines that are parallel to y =2x-5 have the same slope of 2

M=2
6 0
3 years ago
What is the rule for the given sequence? 3, 8, 23, 68, 203,
EleoNora [17]

Answer: Add the number previously added multiplied by 3;

+3x, where x is the number that was added previously

Step-by-step explanation:

3+5=8. That's the first equation, where 5 is x. Then the next equation, 8+3x=23. 8+15=23. It works for all of the equations, so that's the pattern.

4 0
3 years ago
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Please consider the following values for the variables X and Y. Treat each row as a pair of scores for the variables X and Y (wi
Studentka2010 [4]

Answer:

The Pearson's coefficient of correlation between the is 0.700.

Step-by-step explanation:

The correlation coefficient is a statistical degree that computes the strength of the linear relationship amid the relative movements of the two variables (i.e. dependent and independent).It ranges from -1 to +1.

The formula to compute correlation between two variables <em>X</em> and <em>Y</em> is:

r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}

The formula to compute covariance is:

Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y

The formula to compute the variances are:

V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}

Consider the table attached below.

Compute the covariance as follows:

Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y

                 =(5\times 165)-(30\times 25)\\=75

Thus, the covariance is 75.

Compute the variance of X and Y as follows:

V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\=(5\times 226)-(30)^{2}\\=230\\\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}\\=(5\times 135)-(25)^{2}\\=50

Compute the correlation coefficient as follows:

r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}

            =\frac{75}{\sqrt{230\times 50}}

            =0.69937\\\approx0.70

Thus, the Pearson's coefficient of correlation between the is 0.700.

5 0
3 years ago
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