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DedPeter [7]
3 years ago
13

A 13.00 g sample of citric acid reacts with an excess of baking soda as shown in the equation. What is the theoretical yield of

carbon dioxide?
Chemistry
2 answers:
Mariulka [41]3 years ago
6 0
The answer on the quiz would be (d) 8.93 g 
julia-pushkina [17]3 years ago
3 0
Chemical equation of the reaction between citric acid and baking soda:

C_{6}  H_{8}  O_{7} +3NaHCO_{3} -\ \textgreater \  Na_{3} C_{6} H_{5} O_{7} +3 H_{2} O+3CO_{2}

Ratios

Citric Acid        Baking soda    ->  Sodium Citrate  Water    Carbon Dioxide
C6H8O7                                                                                CO2
1 mole                                                                                     3moles

Molecular masses
Citric acid
6*12 + 8*1 + 7*16 = 192 g/mole
Carbon dioxide
12 + 2*16 =   44 g/mole

Proportion carbon dioxide / citric acid

3 * 44 g of carbon dioxide / 192 g of citric acid

132 g of carbon dioxide / 192 g of citric acid

13.00 g of citric acid * [132 g of carbon dioxide / 192 g of citric acid] =  8.94 g of carbon dioxide.

Answer: 8.94 grams.
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What is the density of a substance that has a volume of 14 millimeters and a mass of 13.2 grams.
Contact [7]

Answer:

<h2>0.94 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question we have

density =  \frac{13.2}{14}  \\  = 0.94285...

We have the final answer as

<h3>0.94 g/mL</h3>

Hope this helps you

6 0
2 years ago
How do valence electrons interact between non polar covalent, polar covalent, and ionic bonds?​
iVinArrow [24]

Answer:

In non-polar covalent bonds, the electrons are equally shared between the two atoms. For atoms with differing electronegativity, the bond will be a polar covalent interaction, where the electrons will not be shared equally.

Explanation:

i did some reasherch so there^^

5 0
3 years ago
A solution of potassium cyanide, KCN, is made by dissolving 3.2 g of KCN in water. When this solution reacts with excess hydroch
Rama09 [41]

Answer:

22.7%

Explanation:

We must first put down the equation of reaction to guide our work while solving the problem.

KCN(aq) + HCl (aq)--> KCl(aq) + HCN(aq)

The questions specifically state that HCl is in excess so KCN is the limiting reactant.

Number of moles of KCN reacted= mass of KCN reacted / molar mass of KCN

Mass of KCN reacted= 3.2 g

Molar mass of KCN= 65.12 g/mol

Number of moles of KCN= 3.2/65.12 g/mol= 0.049 moles

Theoretical yield of HCN is obtained thus;

From the reaction equation;

1 mol of KCN produced 1 mole of HCN thus 0.049 moles of KCN will produce 0.049 moles of HCN.

Mass of HCN = number of moles ×molar mass

Molar mass of HCN= 27.0253 g/mol

Hence mass of HCN produced= 0.049mol × 27.0253 g/mol= 1.32g of HCN

Actual yield of HCN= 0.30g

% yield= actual yield/ theoretical yield ×100

% yield= 0.30/1.32 ×100

%yield= 22.7%

3 0
3 years ago
Read 2 more answers
Which of the following will produce a precipitate?
nekit [7.7K]

Reaction of option c produces precipitate.

Rhodium on reacting with potassium phosphate produces rhodium phosphate which remain in solution due to low lattice energy for rhodium phosphate.

Niobium on reacting with lithium carbonate produces niobium carbonate and it will remain in aqueous form.  

Cobalt on reacting with zinc nitrate produces cobalt nitrate. This, Co(NO3 )2 is insoluble precipitate and settles at bottom whereas zinc ion will remain in solution as follows:

Co^2^+ + Zn(NO¬_3 )¬_2    Co(NO¬_3 )¬_2    + Zn^2^+

Potassium ion on reacting with sodium sulfide produces potassium sulfide which remain in solution  


8 0
3 years ago
An iron bar at 200c is placed in thermal contact with an identical iron bar at 120c in an isolated system
Step2247 [10]

Conduction: In the conduction, the heat is transferred from the hotter body to the colder body until the temperature on both bodies are equal.

In thermal equilibrium, there is no heat transfer as the heat is transferred till the temperature on the bodies are not same.

In the given problem, an iron bar at 200°C is placed in thermal contact with an identical iron bar at 120°C in an isolated system. After 30 minutes, the thermal equilibrium is attained. Then, the temperature on both iron bars are equal.Both iron bars are at 160°C in an isolated system.

But in an open system, the temperatures of the iron bars after 30 minutes would be less than 160°C. There will be heat lost to the surrounding. The room temperature is 25°C. There will be exchange of the heat occur between the iron bars and the surrounding. But It would take more than 30 minutes for both iron bars to reach 160°C because heat would be transferred less efficiently.

7 0
3 years ago
Read 2 more answers
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