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elena-14-01-66 [18.8K]
3 years ago
13

Hey! May someone do these? False/incomplete are instant report!

Physics
2 answers:
Lyrx [107]3 years ago
7 0
For the student box thing I believe it was the grass or carpet I hope this helps a little
Tatiana [17]3 years ago
3 0

Answer:

Friction is a force

Friction makes a moving object slow down

Type of friction: Air resistance

Surface with most friction is surface 2 because the cup is the highest up

Option 2 is the one that makes the car go forward

ice has the least friction

Explanation:

i am a scientist

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Referring to the graph below of data describing a cart pulled across a level surface. When a 4 N force pulls on the cart, the ca
LenKa [72]

Answer:gjv

Explanation:

4 0
3 years ago
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If a quasar is moving away from us at v/c = 0.8, what is the measured redshift?
Delicious77 [7]

Answer:

The measured redshift is z =2

Explanation:

Since the object is traveling near light speed, since v/c = 0.8, then we have to use a redshift formula for relativistic speeds.

z= \sqrt{\cfrac{c+v}{c-v}}-1

Finding the redshift.

We can prepare the formula by dividing by lightspeed inside the square root to both numerator and denominator to get

z= \sqrt{\cfrac{1+\cfrac vc}{1-\cfrac vc}}-1

Replacing the given information

z= \sqrt{\cfrac{1+0.8}{1-0.8}}-1

z= \sqrt{\cfrac{1.8}{0.2}}-1\\z= \sqrt{9}}-1\\z=3-1\\z=2

Thus the measured redshift is z = 2.

4 0
3 years ago
The rate at which heat enters an air conditioned building is often roughly proportional to the difference in temperature between
erma4kov [3.2K]

Answer:

Considering first question

    Generally the coefficient of performance of the air condition  is mathematically represented as

   COP  =  \frac{T_i}{T_o - T_i}

Here T_i is the inside temperature

while  T_o is the outside temperature

What this coefficient of performance represent is the amount of heat the air condition can remove with 1 unit of electricity

So it implies that the air condition removes   \frac{T_i}{T_o - T_i} heat with 1 unit of electricity

Now from the question we are told that the rate at which heat enters an air conditioned building is often roughly proportional to the difference in temperature between inside and outside. This can be mathematically represented as

         Q \ \alpha \ (T_o - T_i)

=>        Q= k (T_o - T_i)

Here k is the constant of proportionality

So  

    since  1 unit of electricity  removes   \frac{T_i}{T_o - T_i}  amount of heat

   E  unit of electricity will remove  Q= k (T_o - T_i)

So

      E =  \frac{k(T_o - T_i)}{\frac{T_i}{ T_h - T_i} }

=>   E = \frac{k}{T_i} (T_o - T_i)^2

given that  \frac{k}{T_i} is constant

    =>  E \  \alpha  \  (T_o - T_i)^2

From this above equation we see that the  electricity required(cost of powering and operating the air conditioner) is approximately proportional to the square of the temperature difference.

 Considering the  second question

Assuming that  T_i   =  30 ^oC

 and      T_o  =  40 ^oC

Hence  

     E = K (T_o - T_i)^2

Here K stand for a constant

So  

        E = K (40 -  30)^2

=>      E = 100K

Now if  the  T_i   =  20 ^oC

Then

       E = K (40 -  20)^2

=>      E = 400 \ K

So  from this see that the electricity require (cost of powering and operating the air conditioner)when the inside temperature is low  is  much higher than the electricity required when the inside temperature is higher

Considering the  third question

Now in the case where the  heat that enters the building is at a rate proportional to the square-root of the temperature difference between inside and outside

We have that

       Q = k (T_o - T_i )^{\frac{1}{2} }

So

       E =  \frac{k (T_o - T_i )^{\frac{1}{2} }}{\frac{T_i}{T_o - T_i} }

=>   E =  \frac{k}{T_i} * (T_o - T_i) ^{\frac{3}{2} }

Assuming \frac{k}{T_i} is a constant

Then  

     E \ \alpha \ (T_o - T_i)^{\frac{3}{2} }

From this above equation we see that the  electricity required(cost of powering and operating the air conditioner) is approximately proportional to the square root  of the cube of the  temperature difference.

   

4 0
3 years ago
. A weather balloon is inflated to a volume of 2.2 x 103 L with 37.4 g of helium. What is the density of helium in grams per lit
Margarita [4]
That is the mst best eway to find its solution.
37.4/2.2*10^3 =  0.017 gm/liter or  1.7*10^-2
so we conclude that option b is sorrect
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Which of the following is an important step in the process of conflict resolution?
4vir4ik [10]
A would be the correct answer. Its the only one to make sense since you are trying to solve the conflict!
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4 years ago
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