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Levart [38]
3 years ago
15

Consider a household that uses 14,000 kWh of electricity and 900 gal of fuel oil, per year, during a heating season. The average

amount of CO2 produced is 26.4 lbm/gal of fuel oil and 1.54 lbm/kWh of electricity. If this household reduces its oil and electricity usage by 21 percent by implementing some energy conservation measures, determine the reduction in the amount of CO2 emissions by that household per year.
Physics
1 answer:
ryzh [129]3 years ago
7 0

Answer:

9517.2 lbm

Explanation:

Electricity consumption = 14000 kWh/year

Fuel consumption = 900 gal/year

Amount of CO₂ produced per gallon = 26.4 lbm/gal

Amount of CO₂ produced per kWh = 1.54 lbm/kWh

Amount of CO₂ produced in one year

14000\times 1.54+900\times 26.4=45320\ lbm

Reduction would be

0.21\times 45320=9517.2\ lbm

The reduction in the amount of CO₂ produced is 9517.2 lbm

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The athlete is doing work because he prevents the weight from falling downward
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A capacitor has a charge of 4.6 μC. An E-field of 1.8 kV/mm is desired between the plates. There's no dielectric. What must be
Scrat [10]

Answer:

A = 0.2875 m^2

Explanation:

As we know that

Q = 4.6 \mu C

E = 1.8 kV/mm

now we know that electric field between the plated of capacitor is given as

E = \frac{\sigma}{\epsilon_0}

now we will have

1.8 \times 10^6 = \frac{\sigma}{\epsilon_0}

\sigma = (1.8 \times 10^6)(8.85 \times 10^{-12})

\sigma = 1.6 \times 10^{-5} C/m^2

now we have

\sigma = \frac{Q}{A}

now we have area of the plates of capacitor

A = \frac{Q}{\sigma}

A = \frac{4.6 \times 10^{-6}}{1.6 \times 10^{-5}}

A = 0.2875 m^2

5 0
3 years ago
The _________ specifies the station that sent the frame.
german

<span>Ans: The source Address field specifies the station that sends the frame. 

The format of an Ethernet frame includes a destination address at the beginning which contains the address of the device which is sending the frame. And, the source address tells us which station the information is received from. </span>

3 0
3 years ago
relationship beetween image distance,focal length ,power magnification, for both concave and convex lens.​
scoray [572]

Answer:

Object distance means what is the distance between pole and object. Image distance means when image is formed then the distance between pole and image is called image distance. Focal length is the distance between pole and the principal focus of the mirror.

A lens is a clear object, usually made of glass or plastic, which is used to refract, or bend light. Lenses can concentrate light rays (bring them together) or spread them out. Common examples of lenses include camera lenses, telescope lenses, eyeglasses, and magnifying glasses. Lenses are often double lenses, meaning they have two curved sides. A convex lens is rounded outward, while a concave lens curves inward. (A great way to remember this is that a concave lens creates an indent like a cave!)

The image distance can be calculated with the knowledge of object distance and focal length with the help of lens formula. In optics, the relationship between the distance of an image (i), the distance of an object (o), and the focal length (f) of the lens are given by the formula known as Lens formula. Lens formula is applicable for convex as well as concave lenses. These lenses have negligible thickness. It is an equation that relates the focal length, image distance, and object distance for a spherical mirror. It is given as,

1/i + 1/o = 1/f

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o= distance of the object from the lens

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Explanation:

Hope it is helpful....

7 0
2 years ago
Read 2 more answers
Nerve cells transmit electric signals through their long tubular axons. These signals propagate due to a sudden rush of Na+ ions
iren [92.7K]

Answer:

I = \frac{9.12x10^{-8} C}{0.007 s}= 1.30285 x10^{-5} \frac{C}{s}=1.30285 x10^{-5} A = 13.02 \mu A

Explanation:

For this case we have the following info given:

Number of Na+ ions 5.7 x10^{11} ions

Each ion have a charge of +e and the crage of the electron is 1.6 x10^{-19}C

The time is given t = 7 ms if we convert this into seconds we got:

t = 7ms * \frac{1s}{1000 ms}= 0.007s

Now we can use the following formula given from the current passing thourhg a meter of nerve axon given by:

Q = Ne

Where N represent the number of ions, e the charge of the electron and Q the total charge

If we replace on this case we have this:

Q= 5.7x10^{11} * (1.6 x10^{-19}C) = 9.12x10^{-8} C

And from the general definition of current we know that:

I =\frac{Q}{t}

And since we know the total charge Q and the time we can replace:

I = \frac{9.12x10^{-8} C}{0.007 s}= 1.30285 x10^{-5} \frac{C}{s}=1.30285 x10^{-5} A = 13.02 \mu A

The current during the inflow charge in the meter axon for this case is 13.02 \mu A

3 0
3 years ago
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