Answer:
The angular acceleration is 11.66 rad/s²
Explanation:
Step 1: Given data
Three forces are applied to a solid cylinder of mass 12 kg
F1 = 15 N
F2 = 24 N
F3 = 19 N
R2 = 0.22m
R3 = 0.10m
Step 2: Find the magnitude of the angular acceleration
I = ½mr² = ½ * 12kg * (0.22m)² = 0.29 kg*m²
torque τ = I*α
τ = F2*R2 - F1*R1 = 24N*0.22m - 19N*0.10m = 3.38 N*m
This means
I = ½mr² = 0.29 kg*m²
τ = I*α = 3.38 N*m
OR
0.29 kg*m² * α = 3.38 N*m
α = 11.655 rad/s² ≈11.66 rad/s²
The angular acceleration is 11.66 rad/s²
In a reversible reaction, both forward and reverse directions of the reaction generally occur at the same time. While reactants are reacting to produce products, products are reacting to produce reactants. Often, a point is reached at which forward and reverse directions of the reaction occur at the same rate.
Answer:
36.408cm3
Explanation:
Since we acknowledge that density is d= m/v, once we switch it up to maintain v as the number to be found it will change to v=m/d. Therefore, 275.32/7.562 is 36.408 and the unit is cm cube!
Hope that helped!!
Density can be any number, as long as it has the right units.
A unit of density has to be (a unit of mass) divided by (a unit of volume).
The most common one is gram/cm^3.
