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3 years ago

A piece of fruit falls straight down. As it falls,

Physics

1 answer:

Allisa [31]3 years ago

4 0

Answer:

Explanation:

The gravitational force does positive work on it and the gravitational potential energy decreases.

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Air flows through a nozzle at a steady rate. At the inlet the density is 2.21 kg/m3 and the velocity is 20 m/s. At the exit, the

Vitek1552 [10]

To solve the problem, it is necessary to apply the concepts related to the change of mass flow for both entry and exit.

The general formula is defined by

$\dot{m}=\rho A V$

Where,

$\dot{m} =$ mass flow rate

$\rho =$ Density

V = Velocity

Our values are divided by inlet(1) and outlet(2) by

$\rho_1 = 2.21kg/m^3$

$V_1 = 20m/s$

$A_1 = 60*10^{-4}m^2$

$\rho_2 = 0.762kg/m^3$

$V_2 = 160m/s$

PART A) Applying the flow equation we have to

$\dot{m} = \rho_1 A_1 V_1$

$\dot{m} = (2.21)(60*10^{-4})(20)$

$\dot{m} = 0.2652kg/s$

PART B) For the exit area we need to arrange the equation in function of Area, that is

$A_2 = \frac{\dot{m}}{\rho_2 V_2}$

$A_2 = \frac{0.2652}{(0.762)(160)}$

$A_2 = 2.175*10^{-3}m^2$

Therefore the Area at the end is $21.75cm^2$

3 0

3 years ago

A long, straight wire of radius R carries a steady current I that is uniformly distributed through the cross section of the wire

vitfil [10]

Answer:

When $r \ge R$

$B = \frac{ \mu_o * I}{ 2 \pi r }$

When $r< R$

$B = [\frac{\mu_o * I }{ 2 \pi R^2} ]* r$

Explanation:

From the question we are told that

The radius is R

The current is I

The distance from the center

Ampere's law is mathematically represented as

$B[2 \pi r] = \mu_o * \frac{I r^2 }{R^2 }$

$B = \frac{ \mu_o}{2 \pi } * \frac{r}{R^2}$

When $r \ge R$

=> $B = \frac{ \mu_o * I}{ 2 \pi r }$

But when $r< R$

$B = [\frac{\mu_o * I }{ 2 \pi R^2} ]* r$

4 0

3 years ago

Round the following off to required number of significant figures.

Stells [14]

Answer:

140

hope this helps

have a good day :)

Explanation:

4 0

2 years ago

Read 2 more answers

The force of gravity on a person or object on the surface of a planet is called

viva [34]

Answer:

D. Weight

Explanation:

Hope that helps:)

3 0

2 years ago

Read 2 more answers

una onda longitudinal tiene una frecuencia de 200 hz y una longitud de onda de 4.2m ¿cual es la rapidez de la onda?

swat32

Answer:

v = 8.4 m/s

Explanation:

The question ays, "A longitudinal wave has a frequency of 200 Hz and a wavelength of 4.2m. What is the speed of the wave?".

Frequency of a wave, f = 200 Hz

Wavelength = 4.2 cm = 0.042 m

We need to find the speed of the wave. The formula for the speed of a wave is given by :

$v=f\lambda\\\\v=200\times 0.042\\\\=8.4\ m/s$

So, the speed of the wave is equal to 8.4 m/s.

4 0

2 years ago