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maw [93]
3 years ago
14

Winds tend to rotate in a counter clockwise direction in the ___ (northern or southern) Hemisphere as they move into a low press

ure area.
Physics
2 answers:
lana [24]3 years ago
8 0

Answer:

Winds tend to rotate in a counter clockwise direction in the center of northern and southern hemisphere.

Explanation:

The wind blows clockwise around a high pressure area  in the northern hemisphere and the wind blows counter - clockwise around low pressure.  

In the northern hemisphere High-pressure systems rotate clockwise direction and in the southern hemisphere  low-pressure systems rotate clockwise direction.

 

Troyanec [42]3 years ago
8 0

Answer:

<u>Southern.</u>

Explanation:

In the <em>northern hemisphere</em>, the turn of the earth causes the <u>winds to curve to the right </u>and to the left in the southern hemisphere.  With a<em> high pressure </em>system, the air is <u>forced outward</u> and the Earth's turn eastward creates a clockwise flow.

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An ideal spring hangs from the ceiling. A 1.25-kg mass is hung from the spring. After all vibrations have died away, the spring
ch4aika [34]

The kinetic energy of the mass at the instant it passes back through its equilibrium position is about 1.20 J

\texttt{ }

<h3>Further explanation</h3>

Let's recall Elastic Potential Energy formula as follows:

\boxed{E_p = \frac{1}{2}k x^2}

where:

<em>Ep = elastic potential energy ( J )</em>

<em>k = spring constant ( N/m )</em>

<em>x = spring extension ( compression ) ( m )</em>

Let us now tackle the problem!

\texttt{ }

<u>Given:</u>

mass of object = m = 1.25 kg

initial extension = x = 0.0275 m

final extension = x' = 0.0735 - 0.0275 = 0.0460 m

<u>Asked:</u>

kinetic energy = Ek = ?

<u>Solution:</u>

<em>Firstly , we will calculate the spring constant by using </em><em>Hooke's Law</em><em> as follows:</em>

F = k x

mg = k x

k = mg \div x

k = 1.25(9.8) \div 0.0275

k = 445 \frac{5}{11} \texttt{ N/m}

\texttt{ }

<em>Next , we will use </em><em>Conservation of Energy</em><em> formula to solve this problem:</em>

Ep_1 + Ek_1 = Ep_2 + Ek_2

\frac{1}{2}k (x')^2 + mgh + 0 = \frac{1}{2}k x^2 + Ek

Ek = \frac{1}{2}k (x')^2 + mgh - \frac{1}{2}k x^2

Ek = \frac{1}{2}k ( (x')^2 - x^2 ) + mgh

Ek = \frac{1}{2}(445 \frac{5}{11}) ( 0.0460^2 - 0.0275^2 ) + 1.25(9.8)(0.0735)

\boxed {Ek \approx 1.20 \texttt{ J}}

\texttt{ }

<h3>Learn more</h3>
  • Kinetic Energy : brainly.com/question/692781
  • Acceleration : brainly.com/question/2283922
  • The Speed of Car : brainly.com/question/568302
  • Young Modulus : brainly.com/question/9202964
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\texttt{ }

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Elasticity

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What is a main difference between the Schrodinger model and the bohr atomic model
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Schrodinger's<span> wave... Energy: The </span>Bohr model<span> and the Quantum Mechanical </span>model<span>of the </span>atom<span> both assign specific energies to an electron. ... Positions Occupied by Electrons: The </span>main<span> similarity </span>between<span> the two </span>models<span> is that in both electrons are</span>different<span> distances from the nucleus, corresponding to </span>different<span> energies.

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Consider a turntable to be a circular disk of moment of inertia It rotating at a constant angular velocity ωi around an axis thr
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Answer:

Note: Angular momentum is always conserved in a collision.

The initial angular momentum of the system is

L = ( It ) ( ωi )

where It = moment of inertia of the rotating circular disc,

ωi = angular velocity of the rotating circular disc

The final angular momentum is

L = ( It + Ir ) ( ωf )

where ωf is the final angular velocity of the system.

Since the two angular momenta are equal, we see that

( It ) ( ωi ) = ( It + Ir ) ( ωf )

so making ωf the subject of the formula

ωf = [ ( It ) / ( It + Ir ) ] ωi

Explanation:

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Why are strokes and Alzheimer's disease serious conditions? Select all that apply. You can die from either one.
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The first and fourth option my dudette
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Two loudspeakers are located 4.965 m apart on an outdoor stage. A listener is 12.608 m from one and 18.368 m from the other. Dur
leonid [27]

Answer:

Approximately 30.0\; \rm Hz.

Explanation:

Look up the speed of sounds in the air at 25\; ^\circ\rm C: v \approx 346\; \rm m \cdot s^{-1}.

Let the frequency of this tune be f\; \rm Hz. The wavelength of the tune would be \displaystyle \lambda = \frac{v}{f} \approx \frac{346}{f}.

The distance between the first speaker and the listener is 12.608\; \rm m. How many wavelengths can fit into that distance?

\displaystyle \frac{12.608}{\lambda} \approx \frac{12.608}{346 / f} = \frac{12.608}{346} \cdot f.

Similarly, the distance between the second speaker and the listener is 18.368\; \rm m. Number of wavelengths in that distance:

\displaystyle \frac{18.368}{\lambda} \approx \frac{18.368}{346 / f} = \frac{18.368}{346} \cdot f.

Difference between these two numbers:

\begin{aligned} &\frac{18.368}{346} \cdot f - \frac{12.608}{346} \cdot f = \frac{5.76}{346}\cdot f\end{aligned}.

For destructive interference to occur, that difference should be equal to \displaystyle \frac{1}{2}, \displaystyle 1 + \frac{1}{2}= \frac{3}{2}, \cdots, or  \displaystyle \left(k+ \frac{1}{2}\right) in general (k can be any non-negative whole number.)

Let \begin{aligned} \frac{5.76}{346}\cdot f = k + \frac{1}{2}\end{aligned}, and solve for f.

\begin{aligned} f&= \left.\left(k + \frac{1}{2}\right) \right/\frac{5.76}{346}\\ &= \frac{346}{5.76} \, k + \frac{1}{2} \times \frac{346}{5.76} \\ &\approx 60.1\, k + 30.0 \end{aligned}.

The next step is to find the values of k that ensure 20 \le f \le 20\times 10^{3} (frequency is between 20\; \rm Hz and 20\, \rm kHz.) It turns out that k = 0 (the smallest k value possible) would be sufficient. In that case, the frequency is approximately 30.0\; \rm Hz. Using a larger k would only increase the frequency.

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3 years ago
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