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svet-max [94.6K]
3 years ago
7

Presence of _______- in retina gives us night vision that is help us to see in dim light.Required to answer. Single choice. Imme

rsive Reader (1 Point) cornea retina lens rods
Physics
1 answer:
qwelly [4]3 years ago
7 0

Answer: Rods

Explanation:

The rod cells in the retina are the reason we are able to see at night and in dim light. They exist on the edges of the retina which is why they are also very useful for the peripheral vision of a human.

Rod cells number over 90 million in the eyes and although very useful for seeing in dimmer light, they are not very useful for color vision which is why humans see less colors in the dark.

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Which of the following is a product in the process of photosynthesis?
Leona [35]

Answer:

  1. glucose is the product in the process of photosynthesis
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Which observational tool helped astronomers Arno Penzias and Robert Wilson discover the existence of the cosmic microwave backgr
Softa [21]
<span>In 1964, while experimenting with the Holmdel Horn Antenna, which was used as a radio telescope, Penzias and Wilson accidentally discovered the microwave background radiation that exists universally. The Holmdel Horn Antenna was used to support the "Big Bang Theory" as opposed to the "Steady State Theory".</span>
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If the light rays in the incident ray originate at 20º from the surface...
Ainat [17]

Given :

The light rays in the incident ray originate at 20º from the surface.

To Find :

The angle for the incident ray.

Solution :

We know angle of incidence is measured from perpendicular to the surface .

So,

\theta_i = 90^o - 20^o\\\\\theta_i = 70^o

Now, we know by law of reflection :

Angle of reflection = Angle of incident

\theta_r = 70^o

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5 0
3 years ago
A piston motion moves a 25-kg hammerhead vertically down 1 m from rest to a velocity of 50 m/s in a stamping machine. What is th
Alja [10]

Answer:

31.005 KJ

Explanation:

We are given that

Mass of hammerhead=25 kg

Initial velocity,u=0

Final velocity,v=50 m/s

h=-1 m

h'=0

We have to find the change in total energy of the hammerhead.

Change in total energy=E_2-E_1=m(u_2-u_1)+\frac{1}{2}m(v^2-u^2)+mg(h-h')

Using the formula

Change in internal energy of hammerhead=m(u_2-u_1)=0

Change in total energy=\frac{1}{2}(25)(50)^2+25\times 9.8(-1)

Where g=9.8m/s^2

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1 KJ=1000 J

3 0
3 years ago
Becky has a shower and uses 20,000g of water with a specific heat capacity of 4200J/KG. When the water is supplied with 336,000J
lara [203]

Answer:

46°C

Explanation:

q = mCΔT

336,000 J = (20 kg) (4200 J/kg/°C) (50°C − T)

T = 46°C

7 0
3 years ago
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