Explanation:
S =ut + 1/2at^2
S = 0×6.5 + (1/2 × 9.54) × 6.5^2
S =0 + 4.77 ×42.25
S=201.5m
Answer:
The total displacement is 102 km north of east.
Explanation:
We can treat this problem as a trigonometric one, so we need to calculate the total displacement on the north and east.
and
The total displacement is given by:
with an agle of:
<span>it fairly is going to attain a speed of 24 m/s in a 2d, yet between t = 0 and t = a million, it fairly is not any longer vacationing at that speed, yet at slower speeds. it fairly is 12 meters. ?D = [ ( a?T^2 + 2?Tv_i ) ] / 2 the place: ?D = displacement a = acceleration ?T = elapsed time v_i = preliminary speed ?D = [ ( 24m/s^2 • 1s • 1s + 2 • 1s • 0m/s ) ] / 2 ?D = 24 / 2 ?D = 12m</span>
Explanation:
1. Acceleration is the change in velocity over time.
a = Δv / Δt
a = (29.8 m/s − 37.1 m/s) / 3 s
a = -2.43 m/s²
2. Work equals force times distance.
W = Fd
W = (87.3 N) (2.04 m)
W = 178 J
3. Power is work per time.
P = W / t
267 W = 1250 J / t
t = 4.68 s
Answer:
what is your question because I seem to not see a question in this question....