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Luden [163]
3 years ago
7

When a substance is oxidized it is called a(n): select one:

Chemistry
1 answer:
BlackZzzverrR [31]3 years ago
4 0
When a substance is oxidized, its oxidation number increases. The reduction in oxidation number is due to lose of electron(s) to another substance in the reactant side. Substance which gets oxidize must reduce others. Thus it is a reducing agent.
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Use the pull-down boxes to specify states such as (aq) or (s). If a box is not needed leave it blank. If no reaction occurs leav
babunello [35]

Answer:

H+  +  OH−  --> H2O

Explanation:

Hydrochloric acid is represented by the chemical formular; HCl. This is an ionic substance so in water it breaks apart into hydrohrn ions; H+ and chloride ions; Cl−. It is a strong acid, hence it completely dissociates.

Potassium Hydroxide is also an ionic substance it also breaks apart in water into potassium ions; K+ and hydroxide ions; OH−. It is a strong base, hence it completely dissociates.

The complete ionic equation for the reaction is given as;

H+  +  Cl−  +  K+  +  OH−  -->  K+  +  Cl−  +  H2O

The Hydrogen ion and the Hydroxide ions combine to form water.

The net ionic equation is given as;

H+  +  OH−  --> H2O

Cl- and K+ ions were cancelled out because they do not undergo any changes therefore are not part of the net ionic equation. They are referred to as spectator ions.

5 0
2 years ago
Draw the lewis structure for phosphoryl chloride. optimize formal charges.
attashe74 [19]
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3 years ago
What are some of the body external defenses
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3 years ago
Identify the examples of diffusion in the list below
Sergeu [11.5K]

Answer:

movement of particles of object from one place to another

e.g

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spreading of ink in water

Explanation:

3 0
3 years ago
Read 2 more answers
A balloon at 25°C has 30 L. What will the balloon's volume at 35°C?
anygoal [31]

The balloon's volume at 35°C : V₂=31.01 L

<h3>Further explanation</h3>

Given

T₁ = 25°C+273 = 298 K

V₁ = 30 L

T₂ = 35 °C + 273 = 308 K

Required

The new volume (V₂)

Solution

Charles's Law  

When the gas pressure is kept constant, the gas volume is proportional to the temperature  

\tt \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

Input the value :

V₂=(V₁.T₂)/T₁

V₂=(30 x 308)/298

V₂=31.01 L

8 0
2 years ago
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