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Phoenix [80]
3 years ago
11

1) Mario's company makes unusually shaped imitation gemstones one gemstone had 12 faces and 20 edges how many vertices did the g

emstone have?
a. 34
b. 10
c. 30
d. 8
Mathematics
1 answer:
kicyunya [14]3 years ago
4 0

Answer:

E = 20 so you're welcome.

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A traffic helicopter descends at 127 m to be 338 m above the ground what was the original height of the helicopter let h be the
Agata [3.3K]

Answer:

Step-by-step explanation:

If the new height is 338m and the helicopter decended 127m to get to that new height then the original height is simply the sum of them both.

H = 338m + 127m

H = 465m

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Brenda has $500 in her bank account Every week, she withdraws $40 for expeses. Without making any deposits, how many weeks can s
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7 weeks

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3 0
3 years ago
ASAP The team plowed 36 rows in 5 hours. The rain slowed their rate by one-half. How many rows could they now plow in 18 hours?
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8 0
4 years ago
What is the solution of
kobusy [5.1K]

Answer:

Third option: x=0 and x=16

Step-by-step explanation:

\sqrt{2x+4}-\sqrt{x}=2

Isolating √(2x+4): Addind √x both sides of the equation:

\sqrt{2x+4}-\sqrt{x}+\sqrt{x}=2+\sqrt{x}\\ \sqrt{2x+4}=2+\sqrt{x}

Squaring both sides of the equation:

(\sqrt{2x+4})^{2}=(2+\sqrt{x})^{2}

Simplifying on the left side, and applying on the right side the formula:

(a+b)^{2}=a^{2}+2ab+b^{2}; a=2, b=\sqrt{x}

2x+4=(2)^{2}+2(2)(\sqrt{x})+(\sqrt{x})^{2}\\ 2x+4=4+4\sqrt{x}+x

Isolating the term with √x on the right side of the equation: Subtracting 4 and x from both sides of the equation:

2x+4-4-x=4+4\sqrt{x}+x-4-x\\ x=4\sqrt{x}

Squaring both sides of the equation:

(x)^{2}=(4\sqrt{x})^{2}\\ x^{2}=(4)^{2}(\sqrt{x})^{2}\\ x^{2}=16 x

This is a quadratic equation. Equaling to zero: Subtract 16x from both sides of the equation:

x^{2}-16x=16x-16x\\ x^{2}-16x=0

Factoring: Common factor x:

x (x-16)=0

Two solutions:

1) x=0

2) x-16=0

Solving for x: Adding 16 both sides of the equation:

x-16+16=0+16

x=16

Let's prove the solutions in the orignal equation:

1) x=0:

\sqrt{2x+4}-\sqrt{x}=2\\ \sqrt{2(0)+4}-\sqrt{0}=2\\ \sqrt{0+4}-0=2\\ \sqrt{4}=2\\ 2=2

x=0 is a solution


2) x=16

\sqrt{2x+4}-\sqrt{x}=2\\ \sqrt{2(16)+4}-\sqrt{16}=2\\ \sqrt{32+4}-4=2\\ \sqrt{36}-4=2\\ 6-4=2\\ 2=2

x=16 is a solution


Then the solutions are x=0 and x=16


5 0
3 years ago
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