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4 years ago

What role does gravity play in the weight of an object?

1 answer:

6 0

In physics, weight is a measure of the force exerted by gravity on a mass.

You probably know that you weigh less on the Moon than on Earth. For instance, if you weigh 100. pounds on Earth, you will weigh 16.6 pounds on the Moon. But, if your mass on Earth is 100 kg, your mass on the Moon is... also 100 kg. Because the amount of matter you have does not change from the Earth to the Moon, but the gravitational force on the Earth is stronger than on the Moon, so you weigh more on Earth.

You can think of gravity pulling a mass toward the center of an object like the Earth. It pulls a lot harder for more massive objects like the Earth than for the Moon. That's why there's a difference in weight.

As a caveat, adding energy or mass to an object will affect its mass. Additionally, general relativity informs us that when something as traveling very near the speed of light, the whole idea of mass equivalency is not exactly true...

You might be interested in

A bomb at rest at the origin of an xy-coordinate system explodes into three pieces. Just after the explosion, one piece, of mass

ValentinkaMS [17]

Answer:

Explanation:

a ) It is given that bomb was at rest initially , so , its momentum before the explosion was zero.

b ) We shall apply law of conservation of momentum along x and y direction separately because no external force acts on the bomb.

If v be the velocity of the third part along a direction making angle θ

with x axis ,

x component of v = vcosθ

So momentum along x axis after explosion of third part = mv cosθ

= 10 v cosθ

Momentum along x of first part = - 5 x 42 m/s

momentum of second part along x direction =0

total momentum along x direction before explosion = total momentum along x direction after explosion

0 = - 5 x 42 + 10 v cosθ

v cosθ = 21

Similarly

total momentum along y direction before explosion = total momentum along y direction after explosion

0 = - 5 x 38 + 10 v sinθ

v sinθ= 21

squaring and and then adding the above equation

v² cos²θ +v² sin²θ = 21² +19²

v² = 441 + 361

v = 28.31 m/s

Tanθ = 21 / 19

θ = 48°

6 0

3 years ago

A particle P with speed 140 m s–1begins to decelerate uniformly at a certain instant while another particle Q starts from rest 6

Natasha2012 [34]

Answer:

i) The motion of both particles are shown on the same speed-time curve included

ii) Approximately 19.5 seconds

Explanation:

We are given that;

Initial velocity of particle, P = 140 m/s

Start time of particle P = 6 s before start time of particle Q

Position of particle Q when velocity is 25 m/s = 125 m

Therefore, from the equation of motion, we have for particle Q;

v² = u² + 2·a·s

Where:

v = Final velocity = 25 m/s

u = Initial velocity = 0 m/s

a = Acceleration

s = Distance covered = 125 m

Therefore;

25² = 0² + 2×a×125

Which gives a = 25²/(2×125) = 2.5 m/s²

The time taken for particle Q to reach 125 m is found from the relation;

s = u·t + 1/2·a·t²

Where:

t = Time of journey

Therefore;

125 = 0×t + 1/2×2.5×t²

Which gives 125 = 1.25 × t²

Hence, t² = 125/1.25 = 100

t = √(100) = 10 s

The equation for particle Q is v = 0 + 2.5×t

Hence, since particle P starts deceleration 6 seconds before the commencement of motion of particle Q, the amount of seconds after the commencement of deceleration of the first particle P that it takes for particle P to come to rest is found as follows;

Hence, at t = 6 + 10 = 16 seconds particle P speed = 25 m/s

From the equation of motion, for particle P (decelerating) we have

v = u - a·t

Where:

v = 25 m/s

u = 140 m/s

t = 16 s

Hence, 25 = 140 - a×16

∴ 16·a = 140 - 25 = 115

a = 115/16 = 7.1875 m/s²

Therefore, the time it takes before particle P comes to rest is found from the same equation of motion, where v = 0 as follows;

v = u - a·t

0 = 140 - 7.1875 × t

∴7.1875·t = 140

t = 140/7.1875 = 19.48 s ≈ 19.5 seconds.

4 0

3 years ago

A static charge is different from an electric current, in that a static charge __

Vesna [10]

Static charge occurs when there is an imbalance of positively and negatively charged atoms, so this one should be the last option that it involves ions as well.

Hope this helps :)

5 0

4 years ago

A wave with a greater amplitude will transfer . . . . \

Orlov [11]

Answer:

More energy

Explanation:

The amount of energy carried by a wave is related to the amplitude of the wave itself. In particular, the amount of energy carried by the wave is proportional to the square of the amplitude of the wave:

$E \propto A^2$

where

E is the energy

A is the amplitude

This means, for instance, that if the amplitude of a wave is doubled, the energy it carries increases by a factor 4.

8 0

3 years ago

Jane does 5 joules of work when she closes her bedroom window. She applies a force of 6 newtons to do the job. How far does she

insens350 [35]

Statement:

Jane does 5 joules of work when she closes her bedroom window. She applies a force of 6 newtons to do the job.

To find out:

The displacement of the window when she pulled it.

Solution:

Work done (W) = 5 J
Force (F) = 6 N
Let the displacement of the window be s.
We know, the formula of work done, i.e., W = Fs
Putting the values in the above formula, we get
5 J = 6 N × s
or, s = (5 ÷ 6) m
or, s = 0.83 m

Answer:

She pulls the window by 0.83 m.

Hope you could understand.

If you have any query, feel free to ask.

4 0

3 years ago