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Nikitich [7]
3 years ago
6

The idea that earth was the center of the universe is an example of ---that has been long dicarded

Physics
1 answer:
Leni [432]3 years ago
4 0

Answer:

Geocentric model of the universe

Explanation:

In the geocentric model of the universe, the earth is the center of the universe. This theory was later replaced by the heliocentric model which places the sun as the center.

This belief was propagated by the ancient Greeks. The geocentric model of the universe was proposed by Ptolemy.

The model suggests that other planetary bodies orbits the earth.

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In a shipping yard, a crane operator attaches a cable to a 1240-kg shipping container and then uses the crane to lift the contai
Firdavs [7]

Answer:

Explanation:

Given

mass of ship =1240 kg

height=37 m

(a)Work done by Tension in cable+work done by gravity =0

Work done by gravity =change in potential energy of mass=-1240\times 9.8\times 37=-449.624 kJ

Thus work done by tension=449.624 kJ

(b)work done by force of gravity=-mg\times h=-1240\times 9.8\times 37=-449.624 kJ

4 0
3 years ago
Read 2 more answers
Match each influence to its correct category
Pie

Answer:

healthful I think! Hope that helped

6 0
2 years ago
Read 2 more answers
A ball on the end of a string is whirled around in a horizontal circle of radius 0.478 m. The plane of the circle is 1.02 m abov
m_a_m_a [10]

Answer:

Explanation:

We shall find first the velocity of ball at the time when string breaks. Let it be v . During its fall on the ground , 1.02 m below, we use the formula

h = 1/2 gt² where t is time of fall .

1.02 = 1/2 x 9.8 x t²

t²= .2081

t = .456

During this time it travels horizontally at distance of 2.5 m with uniform velocity of v

v x .456 = 2.5

v  = 5.48 m /s

centripetal acceleration

= v² / r where r is radius of the circular path

= 5.48² / .478

= 62.82 m /s²

3 0
3 years ago
Ok, so this question is probably really easy but I can't really be bothered to answer it, terrible I know, but I thank all usefu
Dvinal [7]
Without a bulb energy cant go through and it would be an open circuit blocking the energy from coming out.
3 0
3 years ago
A 30-mm-diameter copper rod is 1 m long with a yield strength of 70 MPa. Determine the axial force necessary to cause the diamet
ivolga24 [154]

Explanation:

Given data:

d = 30 mm = 0.03 m

L = 1m

S_{y} = 70 Mpa

Δd = -0.0001d

Axial force = ?

validity of elastic deformation assumption.

Solution:

O'₂ = Δd/d = (-0.0001d)/d = -0.0001

For copper,

v = 0.326      E = 119×10³ Mpa

O'₁ = O'₂/v = (-0.0001)/0.326 = 306×10⁶

∵δ = F.L/E.A    and σ = F/A so,

σ = δ.E/L = O'₁ .E = (306×10⁻⁶).(119×10³) = 36.5 MPa

F = σ . A = (36.5 × 10⁻⁶) . (π/4 × (0.03)²) = 25800 KN

S_{y} = 70 MPa > σ = 36.5 MPa

∵ elastic deformation assumption is valid.

so the answer is

F = 25800 K N            and     S_{y} > σ

3 0
3 years ago
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