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3 years ago

The idea that earth was the center of the universe is an example of ---that has been long dicarded

Physics

1 answer:

Leni [432]3 years ago

4 0

Answer:

Geocentric model of the universe

Explanation:

In the geocentric model of the universe, the earth is the center of the universe. This theory was later replaced by the heliocentric model which places the sun as the center.

This belief was propagated by the ancient Greeks. The geocentric model of the universe was proposed by Ptolemy.

The model suggests that other planetary bodies orbits the earth.

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Which bone would a forensic anthropologist analyze to identify a victim as male or female?

noname [10]

the femmus is the answer

6 0

3 years ago

A 65-kg swimmer pushes on the pool wall and accelerates at 6 m/s^2. The friction experienced by the swimmer is 100 N. How many N

Helga [31]

Answer:

490N

Explanation:

According Newton's second law!

\sum Force = mass × acceleration

Fm - Ff = ma

Fm is the moving force

Ff s the frictional force = 100N

mass = 65kg

acceleration = 6m/s²

Required

Moving force Fm

Substitute the given force into thr expression and get Fm

Fm -100 = 65(6)

Fm -100 = 390

Fm = 390+100

Fm = 490N

Hence the force that will cause two cart to move is 490N

5 0

3 years ago

The kinetic energy K of a moving object varies jointly with its mass m and the square of its velocity v. If an object weighing 4

nata0808 [166]

Answer:

K' = 1777.777 J

Explanation:

Given that

m = 40 kg

v= 15 m/s

K=1000

Given that kinetic energy(K) varies with mass(m) and velocity(v)

K= C(mv²)

Where

C= Constant

m=mass

v=velocity

When

m = 40 kg ,v= 15 m/s ,K=1000

K= C(mv²)

1000 = C( 40 x 15²)

C=0.111111

When m = 40 kg and v= 20 m/s

K' = C(mv²)

K= 0.1111 x (40 x 20²)

K' = 1777.777 J

5 0

3 years ago

Read 2 more answers

A 25.0-kg child is standing at the edge of a horizontal merry-go-round with a radius of 2.40 m and a moment of inertia of 356 kg

motikmotik

Answer:

$\omega_{f}=1.634\ rad/s$

Explanation:

given,

diameter of merry - go - round = 2.40 m

moment of inertia = I = 356 kg∙m²

speed of the merry- go-round = 1.80 rad/s

mass of child = 25 kg

initial angular momentum of the system

$L_i = I\omega_i$

$L_i =356\times 1.80$

$L_i =640.8\ kg.m^2/s$

final angular momentum of the system

$L_f = (I_{disk}+mR^2)\omega_{f}$

$L_f = (356 + 25\times 1.2^2)\omega_{f}$

$L_f= (392)\omega_{f}$

from conservation of angular momentum

$L_i = L_f$

$640.8= (392)\omega_{f}$

$\omega_{f}=1.634\ rad/s$

8 0

3 years ago

Read 2 more answers

A wire with a length of 150 m and a radius of 0.15 mm carries a current with a uniform current density of 2.8 x 10^7A/m^2. The c

Mrac [35]

Answer:

The current is 2.0 A.

(A) is correct option.

Explanation:

Given that,

Length = 150 m

Radius = 0.15 mm

Current density $J=2.8\times10^{7}\ A/m^2$

We need to calculate the current

Using formula of current density

$J = \dfrac{I}{A}$

$I=J\timesA$

Where, J = current density

A = area

I = current

Put the value into the formula

$I=2.8\times10^{7}\times\pi\times(0.15\times10^{-3})^2$

$I=1.97=2.0\ A$

Hence, The current is 2.0 A.

7 0

3 years ago