Answer:
speed for last lap is 247.89 km/h
Explanation:
given data
velocity v1 = 203 km/h
velocity v2 = 199 km/h
no of lap n = 10
to find out
average speed for last lap
solution
we consider here distance d for 1 lap
so in first 9 lap time taken is
t1 = distance / velocity v2
t1 = 9d / 199 ...............1
and
for 10 lap time is
t2 = 10d / 203 .............2
so from 1 and 2 equation time for last lap
last lap time t3 = t2 - t1
t3 = 10d / 203 - 9d / 199
t3 = 0.004034 d
so speed for last lap is
speed = distance / time
speed = d / 0.004034 d
speed = 247.89 km/h
so speed for last lap is 247.89 km/h
Answer:
The amount of gravitational potential energy an object has depends on its height and mass. The heavier the object and the higher it is above the ground, the more gravitational potential energy it holds. Gravitational potential energy increases as weight and height increases.
Explanation:
vf^2 = 2ad
vf^2 = 2(9.81)(44m)
vf^2 = 863.28
vf = √863.28
vf = 29.4 - using equations of motion
ME = PE + KE
ME = mgh + 1/2mv^2
ME = (1)(9.81)(44) + 1/2(1)(3^2)
ME = 431.64 + 4.5
ME = 436.14 - using conservation of energy
hope this helps :)
Answer:
u = - 38.85 m/s^-1
Explanation:
given data:
acceleration = 2.10*10^4 m/s^2
time = 1.85*10^{-3} s
final velocity = 0 m/s
from equation of motion we have following relation
v = u +at
0 = u + 2.10*10^4 *1.85*10^{-3}
0 = u + (21 *1.85)
0 = u + 38.85
u = - 38.85 m/s^-1
negative sign indicate that the ball bounce in opposite directon
Answer:
Power = 130 watt
Explanation:
Power is described as the ability to do work, it is also defined as the amount of work in Joules done in a given time in seconds. Mathematically, it is represented as:
In this example, power is calculated as follows:
Work = 39000 J
Time = 5 minutes
converting the time from minutes to seconds:
1 minute = 60 seconds
∴ 5 minutes = 60 × 5 = 300 seconds
N:B the unit for power can also be represented as Joules/seconds or J/s or JS⁻¹