Answer:
<em>the distance d traveled by the lighter fragment is 58.1 m.</em>
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Explanation:
mass of the lighter fragment = m
the lighter fragment traveled a distance = ?
mass of the heavier fragment = 7m
the distance covered by the heavier fragment = 8.30 m
The two particles will be given the same amount of energy from the explosion. This energy is used to do work by the two fragments.
work done by heavier fragment w = mgd
where m is the mass
g is acceleration due to gravity
d is the distance traveled.
substituting, the work done by the heavier fragment is
w = 7m x g x 8.3 = 58.1mg
The same way, the lighter fragment does work of
w = mgd
equating the two work done since they are given the same amount of energy from the explosion, we have
58.1mg = mgd
mg cancels out, we have
<em>the distance d traveled by the lighter fragment d = 58.1 m</em>
