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Zielflug [23.3K]
3 years ago
10

What are three things you already know about the game of baseball?

Physics
1 answer:
Tatiana [17]3 years ago
4 0

Answer:

Positions

Batting

Pitching

Explanation:

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You nose out another runner to win the 100.000m dash. If your total time for the race was 11.8 seconds and you aced out the othe
daser333 [38]
You completed 100.000 m in 11.800 second

you aced out the other runner by 0.001 seconds

time taken by other runner to finish = 11.800 + 0.001 = 11.801s

speed of other runner = 100/11.801 m/s

distance covered by him in 11.8 s = 100/11.801 × 11.8 = 99.992 m

you won by = 100 - 99.992 = 0.008 meter
3 0
4 years ago
If the average time it takes for the cart from point 1 to point 2 is 0.2 s, calculate the angle θ from the horizontal of the tra
inn [45]

Answer:

hehe

Explanation:

I dont know because I am a noob ant study

5 0
3 years ago
after the car leaves the platform , gravity causes it to accelerate downward at a rate of 9.8 m/s2. what is the gravitational fo
alexandr1967 [171]

The gravitational force on the car is the force popularly known
as the car's "weight".  Its magnitude is

            (9.8 m/s²) times (the car's mass, in kilograms) .

The unit of this quantity is [newton] .

5 0
3 years ago
A black body radiates heat energy at the rate of 2 x 10 Js" m' at a temperature of 127° C. The temperature
Degger [83]

Answer:

527 ° C

Explanation:

For black body radiation, the power emitted per unit area is directly proportional to the absolute temperature raised to the fourth power:

j = k T⁴

First, convert 127° C to Kelvins:

127° C + 273.15 = 400.15 K

Now find the constant of variation:

2×10⁵ = k (400.15)⁴

k = 7.80×10⁻⁶

Finally, solve for the temperature at the new rate of radiation:

32×10⁵ = (7.80×10⁻⁶) T⁴

T = 800.3

The temperature is 800 K, or about 527 ° C.

5 0
3 years ago
Now, let’s see what happens when the cannon is high above the ground. click on the wheel of the cannon, and drag it upward as fa
Setler79 [48]
The equation for range is:

R = v₀²sin(2θ)/g
To find the maximum R, differentiate the equation and equate to zero. The solution is as follows:

dR/dθ = (v₀²/g)(sin 2θ)
dR/dθ = (v₀²/g)(cos 2θ)(2) = 0
cos 2θ = 0
2θ = cos⁻¹ 0 = 90
θ = 90/2
<em>θ = 45°</em>
5 0
3 years ago
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