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neonofarm [45]
3 years ago
5

Determine the amount of work done on an ideal gas as it is heated in an enclosed thermally insulated cylinder topped with a free

ly moving piston. The cylinder contains of n moles of the gas and the temperature is raised from T1 to T2. The piston has a mass m and a cross sectional area A.
Physics
1 answer:
sp2606 [1]3 years ago
3 0

Answer:

W = 3/2 n (T₁- T₂)

Explanation:

Let's use the first law of thermodynamics

           ΔE = Q + W

in this case the cylinder is insulated, so there is no heat transfer

           ΔE = W

internal energy can be related to the change in temperature

            ΔE = 3/2 n K ΔT

we substitute

           3/2 n (T₂-T₁) = W

as the work is on the gas it is negative

            W = 3/2 n (T₁- T₂)

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determine the metacentric height of a cylinder of 4 m diameter and height of 4m floating in water with its axis vertical, if per
krok68 [10]

Answer:

-0.383 m

Explanation:

Diameter of cylinder = 4m  therefore  r = 2

height of cylinder ( H ) = 4 m

specific gravity = 0.6 ( assumed )

depth of immersion = 'h'

<u>Determine the metacentric height </u>

weight of cylinder in water = water displaced

= 0.6 * 1000 * πr^2* H = 1000 * πr^2* h

= 0.6 * 4 = h

∴ h = 2.4 m

hence the depth of center of buoyancy from free space = h /2 = 1.2 m

The metacentric height can be calculated using the formula below

Gm = Io / Vsubmerged  - BG

attached below is the remaining solution

6 0
3 years ago
A constant force of 120 N pushes a 55 kg wagon across an 8 m level surface. If the wagon was initially at rest, what is the fina
Illusion [34]

Answer:

The kinetic energy of the wagon is 967.0 J

Explanation:

Given that,

Force = 120 N

Mass = 55 kg

Height = 8 m

We need to calculate the kinetic energy of the wagon

Using newtons law

F = ma

\dfrac{120}{55}=a

a =2.2\ m/s^2

Using equation of motion

v^2 =u^2+2as

Where,

v = final velocity

u = initial velocity

s = height

Put the value in the equation

v^2=0+2\times2.2\times8

v=5.93\ m/s

Now, The kinetic energy is

K.E=\dfrac{1}{2}mv^2

K.E=\dfrac{1}{2}\times55\times(5.93)^2

K.E=967.0\ J

Hence, The kinetic energy of the wagon is 967.0 J

3 0
3 years ago
Roberto and Genevieve are trying to separate a mixture of beads using a sifter. The chart below shows the colors and sizes of th
spin [16.1K]

Answer:

2.5 mm

Explanation:

It's just big enough for red and blue to fall through but small enough that yellow will stay in

3 0
3 years ago
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The force of repulsion between two like-charged particles will increase if
svlad2 [7]
If they're brought closer together
5 0
3 years ago
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A transformer has a primary coil with 375 turns of wire and a secondary coil with 1,875 turns. An AC voltage source connected ac
Sonbull [250]

Answer:

The rms voltage (in V) measured across the secondary coil is 459.62 V

Explanation:

Given;

number of turns in the primary coil, Np = 375 turns

number of turns in the secondary coil, Ns = 1875 turns

peak voltage across the primary coil, Ep = 130 V

peak voltage across the secondary coil, Es = ?

\frac{N_P}{N_s} = \frac{E_p}{E_s} \\\\E_s = \frac{N_sE_p}{N_p} \\\\E_s = \frac{1875*130}{375} \\\\E_s = 650 \ V

The rms voltage (in V) measured across the secondary coil is calculated as;

V_{rms} = \frac{V_0}{\sqrt{2} } = \frac{E_s}{\sqrt{2} } \\\\V_{rms} = \frac{650}{\sqrt{2} } = 459.62 \ V

Therefore, the rms voltage (in V) measured across the secondary coil is 459.62 V

7 0
3 years ago
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