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sdas [7]
3 years ago
12

A student makes several observations about a piece of iron. Which observation describes a chemical property of the iron?

Chemistry
1 answer:
Mama L [17]3 years ago
6 0

Answer:

An example of a chemical property of iron would be that it is capable of combining with oxygen to form iron oxide, or rust.

Explanation:

You have no choice listed, so I provided an example.

You might be interested in
What occurs when potassium reacts with chlorine to form potassium<br> chloride?
marissa [1.9K]
Chlorine gas reacts to potassium bromide to form potassium chloride in solution and liquid bromine.

I hope this helps/answers your question! I vaguely remember getting this question before too
5 0
3 years ago
Evaluate the exponential expression (−2)6.
Olegator [25]

A general exponential expression is something like:

A^n

This means that we need to multiply the number A by itself n times.

Using that we will get (-2)^6 = 64

With that definition, we can rewrite:

(-2)^6 = (-2)*(-2)*(-2)*(-2)*(-2)*(-2)

So we just need to solve the above expression.

Also, remember the rule of signs:

(-)*(-) = (+)

We will get:

(-2)*(-2)*(-2)*(-2)*(-2)*(-2) =  [(-2)*(-2)]*[(-2)*(-2)]*[(-2)*(-2)]

                                        =  4*4*4 = 16*4 = 64

Then we got:

(-2)^6 = 64

If you want to learn more, you can read:

brainly.com/question/17172630

6 0
2 years ago
635 mL of a gas is at a pressure of 8.00 atm. What is the volume of the gas at standard pressure (STP)?
Sveta_85 [38]

The new volume at standard temperature and pressure is 5.08 L.

Explanation:

As per the kinetic theory of gases, the volume occupied by gas molecules will be inversely proportional to the pressure of the gas molecules. This is termed as Boyle's law.

So, pressure∝\frac{1}{volume}

Thus, if two pressure and two volumes are given then,

P_{1} V_{1} = P_{2} V_{2}\\

Now, we known the values of P₁ = 8 atm, V₁ = 635 mL, P₂ = 1 atm and V₂ we have to determine. We are considering P₂ = 1 atm, because we have to determine V₂ at standard temperature and pressure. And standard pressure is 1 atm.

8*635*10^{-3}  = 1 *V{2} \\\\V_{2} = \frac{8*635*10^{-3} }{1} =   5.08 L

Thus, the new volume at standard temperature and pressure is 5.08 L.

5 0
2 years ago
a solution is made by dissolving 21.5 grams of glucose (C6H12O6) in 255 grams of water. what is the freezing point depression of
Lesechka [4]
The freezing point depression of the solution or pure substance that is added with the solvent is calculated through the equation,
    
  ΔTf = Kfm

where ΔT is the freezing point depression, Kf is the constant for water given to be -1.86°C/m and m is the molality of the solution. 

Molality is calculated through the equation,
    
    m = number of moles solute/ kg of solvent

Calculation of molality is shown below.
    
   m = (21.5 g C6H12O6)(1 mol/180 g) / (0.255 kg)
     m = 0.468 molal

The freezing point depression is then,
    
   ΔTf = (-1.86°C/m)(0.468 m) = -0.87°C

<em>Answer: -0.87°C</em>
3 0
3 years ago
Which of the following is an aldehyde?
balu736 [363]

Answer:  CH_3CH_2CH_2CHO has aldehyde functional group.

Explanation:

Functional groups are specific group of atoms within molecules that are responsible for the characteristic chemical reactions of those molecules.

A.  CH_3CH_2CH_2COCH_3 has ketone C=O functional group .

B.  CH_3CH_2CH_2COOH has carboxylic acid COOH functional group .

C.  CH_3CH_2CH_2CHO has  aldehyde H-C=O functional group .

D. CH_3CH_2CH_2COOCH_3 has ester RO-C=O functional group .

Thus CH_3CH_2CH_2CHO has aldehyde (CHO) group.

5 0
3 years ago
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