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3 years ago

A student makes several observations about a piece of iron. Which observation describes a chemical property of the iron?

Chemistry

1 answer:

Mama L [17]3 years ago

6 0

Answer:

An example of a chemical property of iron would be that it is capable of combining with oxygen to form iron oxide, or rust.

Explanation:

You have no choice listed, so I provided an example.

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If a 91.3 g piece of aluminum has a density of 2.7 g/cm3, what is its volume in cubic centimeters?

Alex_Xolod [135]

Answer:

<h2>The answer is 34 cm³</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

$volume = \frac{mass}{density} \\$

From the question

mass of aluminum = 91.8 g

density = 2.7 g/cm³

It's volume is

$volume = \frac{91.8}{2.7} \\$

We have the final answer as

Hope this helps you

3 0

3 years ago

What is an example of the strong nuclear force

tresset_1 [31]

I believe the correct answer is A

7 0

3 years ago

Read 2 more answers

Given 0.500 moles of H₂, how many grams of NH₃ would be produced?

Allisa [31]

Answer:

0.333 mol NH₃

Explanation:

N₂ + 3 H₂ ⇆ 2 NH₃

This is the reaction that produces NH₃. Use the mole ratios to solve. For every 3 moles of H₂ that are consumed, 2 moles of NH₃ are produced.

(0.500 mol H₂) × (2 mol NH₃/3 mol H₂) = 0.333 mol NH₃

You will produce 0.333 moles of NH₃.

4 0

3 years ago

I wonder what avocado is made of

Alex17521 [72]

Answer:

The avocado consists of around 73% water, 15% fat, 8.5% carbohydrates — mostly fibers — and 2% protein. Half an avocado, at around 100 grams (g) contains 160 calories ( 1 ).

7 0

3 years ago

If a compound has a composition of 82% nitrogen and 18% hydrogen, what is the empirical formula for this compound

Damm [24]

Answer: The empirical formula for the given compound is $NH_3$

Explanation : Given,

Percentage of H = 18 %

Percentage of N = 82 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of H = 18 g

Mass of N = 82 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{18g}{1g/mole}=18moles$

Moles of Nitrogen = $\frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{82g}{14g/mole}=5.8moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 5.8 moles.

For Hydrogen = $\frac{18}{5.8}=3.10\approx 3$

For Nitrogen = $\frac{5.8}{5.8}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of H : N = 3 : 1

Hence, the empirical formula for the given compound is $NH_3$

3 0

3 years ago