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2 years ago

The specific heat of aluminum is 0.90 J/gC . How much heat is given off when 25 grams of aluminum is cooled from 55 C to 25 C?

Physics

1 answer:

sp2606 [1]2 years ago

8 0

Answer:

2. How many joules of heat are needed to raise the temperature of 10.0 g of aluminum from 22°C to 55°C, if the specific heat of aluminum is 0.90 J/gºC? c=0.90J/g. 9 (2 sigs.)

Explanation:

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A physicist drives through a stop light. When he is pulled over, he tells the police officer that the Doppler shift made the red

Orlov [11]

The physicist traveling, according to his own testimony at -6.6 × 10⁷ m/s.

<h3>How fast was the physicist traveling, according to his own testimony?</h3>

Using the formula for doppler shift for light,

λ' = λ√[(1 + v/c)/(1 - v/c)] where

λ = wavelength of source,
λ' = wavelength of observer,
v = speed of source and
c = speed of light

Given that the driver is moving away from the stop light, we take the driver as the source. Since, the Doppler shift made the red light of wavelength 650nm appear green to him, with a wavelength of 520nm. we have

λ' = wavelength of source = 650 nm,
λ' = wavelength of observer = 520 nm

So, substituting the values of the variables into the equation, we have

λ' = λ√[(1 + v/c)/(1 - v/c)]

520 nm = 650 nm√[(1 + v/c)/(1 - v/c)]

520/650 = √[(1 + v/c)/(1 - v/c)]

0.8 = √[(1 + v/c)/(1 - v/c)]

Squaring both sides, we have

0.8² = (1 + v/c)/(1 - v/c)

0.64 = (1 + v/c)/(1 - v/c)

0.64(1 - v/c) = (1 + v/c)

0.64 - 0.64v/c = 1 + v/c

0.64 - 1 = v/c + 0.64v/c

-0.36 = 1.64v/c

-0.2195 = v/c

v = -0.22c

v = -0.22 × 3 × 10⁸ m/s

v = -0.66 × 10⁸ m/s

v = -6.6 × 10⁷ m/s

So, the physicist traveling, according to his own testimony at -6.6 × 10⁷ m/s.

Learn more about doppler shift for light here:

brainly.com/question/28499579

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1 year ago

The transfer of energy between two objects by electromagnetic waves is called

gizmo_the_mogwai [7]

The answer your looking for is conduction.

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2 years ago

An electron accelerates through a 12.5 V potential difference, starting from rest, and then collides with a hydrogen atom, excit

Yanka [14]

Answer:

Initial state Final state

3 ⇒ 2

3 ⇒ 1

2 ⇒ 1

Explanation:

For this exercise we must use Bohr's atomic model

E = - 13.606 / n²

where is the value of 13.606 eV is the energy of the ground state and n is the integer.

The energy acquired by the electron in units of electron volt (eV)

E = e V

E = 12.5 eV

all this energy is used to transfer an electron from the ground state to an excited state

ΔE = 13.6060 (1 / n₀² - 1 / n²)

the ground state has n₀ = 1

ΔE = 13.606 (1 - 1/n²)

1 /n² = 1 - ΔE/13,606

1 / n² = 1 - 12.5 / 13.606

1 / n² = 0.08129

n = √(1 / 0.08129)

n = 3.5

since n is an integer, maximun is

n = 3

because it cannot give more energy than the electron has

From this level there can be transition to reach the base state.

Initial state Final state

3 ⇒ 2

3 ⇒ 1

2 ⇒ 1

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2 years ago

WHY IS SATURN ONE OF THE COLDEST PLANETS IN OUR SOLAR SYSTEM

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What are the answer choices?

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3 years ago

A 1.2 x10 3 kilogram automobile in motion strikes a 1.0 x 10 -4 kilogram insect as a result the insect is accelerated at a rate

Mariana [72]

According to Newton's second law, the force applied to an object is equal to the product between the mass of the object and its acceleration:
$F=ma$
where F is the magnitude of the force, m is the mass of the object and a its acceleration.

In this problem, the object is the insect, with mass $m=1.0 \cdot 10^{-4} kg$ . The acceleration of the insect is $a=1.0 \cdot 10^2 m/s^2$ , therefore we can calculate the force exerted by the car on the insect:
$F=ma=(1.0 \cdot 10^{-4} kg)(1.0 \cdot 10^2 m/s^2)=0.01 N$

How do we find the force exerted by the insect on the car?
According to Newton's third law (known as action-reaction law), when an object A exerts a force on an object B, object B also exerts a force equal and opposite on object A. Therefore, the force exerted by the insect on the car is equal to the force exerted by the car on the object, so it is 0.01 N.

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3 years ago