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Nina [5.8K]
2 years ago
5

Find the value of x° 40° 65° 70° 100°

Mathematics
2 answers:
Solnce55 [7]2 years ago
6 0

Answer:

= 40°

Step-by-step explanation:

180-115=65°

65+75=140°

180-140=40°

=40°

Nonamiya [84]2 years ago
4 0

Answer:

x + 75 \degree = 115 \degree \\ x = (115 - 75) \degree \\ x = 40 \degree

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A square stepping stone has a side length of 10 1/4 inches.
Svetach [21]

Area=2.5

Step-by-step explanation:

area

area = length \times width

area = 10 \times  \frac{1}{4}

8 0
2 years ago
Read 2 more answers
A map has a scale of 1:5000000000 .
erastova [34]

Considering the definition of scale, you obtain:

  • the real length of the road is 500,000 km.
  • the real area of the farm is 300 hectares.

<h3>Definition of map</h3>

A map is the conventional graphical representation of a portion of the earth or another celestial body that shows the size and position of elements of the landscape according to the selected scale and projection. That is, a map is a representation of a place, at a size smaller than the actual size.

<h3>Definition of scale</h3>

The scale of a cartographic representation, or map scale (m), is the relationship of similarity between the real dimensions of the geographical space represented and those of its image on the map. In general, it is also defined as the ratio of the lengths of a linear element in the plane and its representation on the terrestrial reference surface.

That is, the scale of the map is defined as the proportionality relationship that exists between a distance measured on the ground and its corresponding measurement on the map.

<h3>Real length of the road</h3>

A map has a scale of 1:5000000000. This indicates that 1 unit on the map is equivalent to 5,000,000,000 in reality.

You know that the road on the map is 10 cm or 0.0001 km long (knowing that 1 km= 100,000 cm).

Then you can apply the following rule of three: if by definition of scale 1 km on the map is equivalent to 5,000,000,000 km in reality, 0.0001 km on the map is equivalent to how much distance in reality?

real length of the road=\frac{0.0001 kmx 5,000,000,000 km }{1 km}

<u><em>real length of the road= 500,000 km</em></u>

Finally, the real length of the road is 500,000 km.

<h3>Real area of the farm</h3>

You know that the area of a farm of the map is 6 cm square, 0.0006 m sr 0.00000006 hectares (knowing that 1 cm square= 0.0001 m square and 10,000 m square= 1 hectare).

Then you can apply the following rule of three: if by definition of scale 1 hectare on the map is equivalent to 5,000,000,000 hectares in reality, 0.00000006 hectares on the map is equivalent to how much area in reality?

real area of the farm=\frac{0.00000006 hectaresx 5,000,000,000 hectares }{1 hectare}

<u><em>real area of the farm= 300 hectares</em></u>

Finally, the real area of the farm is 300 hectares.

<h3>Summary</h3>

In summary, you get:

  • the real length of the road is 500,000 km.
  • the real area of the farm is 300 hectares.

Learn more about scale:

brainly.com/question/15394385

brainly.com/question/27928319

brainly.com/question/11001778

brainly.com/question/23134978

#SPJ1

7 0
1 year ago
Who can help me to solve these questions please?
ankoles [38]

Using the given information, length of QR = 16.6 cm

The area of the trapezium is 304.5 cm²

<h3>Calculating area of a trapezium</h3>

From the question we are to calculate the length of QR and the area of trapezium PQRS

In the given diagram,

Let the midpoint of PS be T

Then, we can write that

|OP|² = |OT|² + |PT|²  (<em>Pythagorean theorem</em>)

|OP| = radius = 13 cm

|PT| = 1/2 × PS = 1/2 × 24 cm = 12 cm

∴ 13² = |OT|² + 12²

169 = |OT|² + 144

|OT|² = 169 -144

|OT|² = 25

|OT| = √25

|OT| = 5 cm

Also, let the midpoint of QR be U

Then, we can write that

|OQ|² = |OU|² + |QU|² (<em>Pythagorean theorem</em>)

|OQ| = radius = 13 cm

From the given information,

The distance of QR from O is twice the distance of PS from O

∴ |OU| = 2 × |OT|= 2 × 5 cm = 10cm

Thus,

13² = ||² + 12²

169 = 10² + |QU|²

|QU|² = 169 -100

|QU|² = 69

|QU| = √69

|QU| = 8.3 cm

Now,

Length of QR = 2 × |QU| = 2 × 8.3 cm

Length of QR = 16.6 cm

b)

Area of the trapezium = 1/2(|QR| + |PS|) × |TU|

Area of the trapezium = 1/2(16.6 + 24) × 15

NOTE: |TU| = |OT| + |OU|

Area of the trapezium = 1/2(40.6) × 15

Area of the trapezium = 20.3 × 15

Area of the trapezium = 304.5 cm²

Hence, the area of the trapezium is 304.5 cm²

Learn more on Calculating area of trapezium here: brainly.com/question/3435635

#SPJ1

7 0
2 years ago
Find the sum of the measures of the interior angles of the polygon. 15-gon A. 2340° B. 2520° C. 2160° D. 1170°
Thepotemich [5.8K]

Answer:

2340

Step-by-step explanation:

Formulae for sum of interior angles is 180(n-2)

Whereby n=number of sides

180(15 - 2) \\ 180(13) \\  = 2340degrees

8 0
3 years ago
HELP ASAP PLEASE.
nordsb [41]
The range of the primary phone data is 0.28. 
The range of the secondary phone data is 0.73.
The median of the secondary phone data is 0.48 g larger than the median of the primary phone data.

To find the range of the primary phone data, subtract the largest and the smallest values:
0.35 - 0.07 = 0.28

To find the range of the secondary phone data, subtract the largest and the smallest values:
1.18 - 0.45 = 0.73

To find the median of the primary phone data, arrange the data from least to greatest and then find the middle value:
0.07, 0.08, 0.1, 0.1, 0.12, 0.13, 0.14, 0.22, 0.35 - the middle is 0.12

To find the median of the secondary phone data, arrange the data from least to greatest and then find the middle value:
0.45, 0.45, 0.5, 0.6, 0.6, 0.68, 0.82, 0.91, 1.18 - the middle is 0.6

The median of the secondary phone data, 0.6, is 0.6-0.12 larger than the median of the primary phone data; 0.6-0.12 = 0.48
5 0
3 years ago
Read 2 more answers
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