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3 years ago

Convert the following standard form equations in to slope y-intercept form (y=mx+b)

Mathematics

1 answer:

olganol [36]3 years ago

8 0

4x-3y+18=0

-4 -4

-3y+18=4x

-18 -18

-3y=4x-18

÷-3 ÷-3 ÷-3

1y=-4/3x+6

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The probability that event A occurs is 0.4, and the probability that events A and B both occur is 0.25. If the probability that

ICE Princess25 [194]

Answer:

The probability that event B will occur is 0.45

Step-by-step explanation:

Given;

probability that event A occurs, P(A) = 0.4

the probability that events A and B both occur, P(A ∩ B) = 0.25

the probability that either event A or event B occurs, P(A ∪ B) = 0.6

To determine the probability that event B will occur, we use probability addition rule;

P(A) + P(B) = P(A ∩ B) + P(A ∪ B)

0.4 + P(B) = 0.25 + 0.6

0.4 + P(B) = 0.85

P(B) = 0.85 - 0.4

P(B) = 0.45

Therefore, the probability that event B will occur is 0.45

4 0

2 years ago

Tadashi had a veggie pizza that was cut into 8 equal pieces. He ate 2 pieces and left the other 6 in the box. What fraction of t

Stella [2.4K]

Answer:

1/4

Step-by-step explanation:

2/8= 1/4

8 0

3 years ago

NEED HELP IN SOLVING THIS AREA PROBLEM !!!!!

dezoksy [38]

I’m not sure if it’s add or multiple the sides of each I don’t know if this even helped lol

6 0

3 years ago

Read 2 more answers

Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round y

kupik [55]

Answer:

75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5 pounds.

Step-by-step explanation:

The question is missing. It is as follows:

Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds): 69 104 125 129 60 64

Assume that the population of x values has an approximately normal distribution.

Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.)

75% Confidence Interval can be calculated using M±ME where

M is the sample mean weight of the wild mountain lions ( $\frac{69 +104 +125 +129+60 +64}{6} =91.8$ )

ME is the margin of error of the mean

And margin of error (ME) of the mean can be calculated using the formula

ME= $\frac{t*s}{\sqrt{N} }$ where

t is the corresponding statistic in the 75% confidence level and 5 degrees of freedom (1.30)

s is the standard deviation of the sample(31.4)

N is the sample size (6)

Thus, ME= $\frac{1.30*31.4}{\sqrt{6} }$ ≈16.66

Then 75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5

3 0

3 years ago

Suzie's Nursery is having a sale on two kinds of plants, venus fly traps and bonsai trees.

ANTONII [103]

Answer:

Venus fly trap = 12

Bonsai tree = 17

Step-by-step explanation:

Given that :

Venus fly trap = $3per plant

Bonsai tree = $5 per plant

Number of plants sold = 29

Total cost of plant sold = $121

Let venus fly trap = x ; bonsai tree =y

x + y = 29 ___ (1)

3x + 5y = 121 ____(2)

From (1) :

x = 29 - y

In (2):

3(29 - y) + 5y = 121

87 - 3y + 5y = 121

87 + 2y = 121

2y = 121 - 87

2y = 34

y = 34/2

y = 17

x = 29 - 17

x = 12

Hence,

Venus fly trap = 12

Bonsai tree = 17

7 0

2 years ago