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Drupady [299]
3 years ago
14

ILL MARK BRAINIEST IF YOU DO THIS CORRECTLY!!!

Physics
1 answer:
IRINA_888 [86]3 years ago
8 0

Explanation:

1)5.8m/s

2)5.15m/s^2

3)12.69m/s

4)

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Which of the fluids below would produce the highest pressure at the bottom of a tank for the same fluid depth?
marishachu [46]
The answer is  a property of density. The higher the density, the higher the pressure at the bottom. 

Pressure = mass / Area. So given that the 4 samples occupy the same area at the bottom, the mass is going to be the determining factor. Per given volume, mercury has the largest mass. The answer is A
7 0
3 years ago
Jimothy is riding his bike to his friend's house. He decides to see how fast he can go, and starts pedaling as hard as he can. H
german

Answer:

Final velocity, V = 11.5m/s

Explanation:

Given the following data;

Initial velocity, U = 2.5m/s

Acceleration, a = 1.5m/s²

Time, t = 6secs

To find the final velocity, we would use the first equation of motion

V = U + at

Substituting into the equation, we have

V = 2.5 + 1.5*6

V = 2.5 + 9

Final velocity, V = 11.5m/s

6 0
3 years ago
"A steel rotating-beam test specimen has an ultimate strength of 120 kpsi. Estimate the life of the specimen if it is tested at
MrRissso [65]

Answer:

life (N) of the specimen is 117000  cycles

Explanation:

given data

ultimate strength Su = 120 kpsi

stress amplitude σa = 70 kpsi

solution

we first calculate the endurance limit of specimen Se i.e

Se = 0.5× Su   .............1

Se = 0.5 × 120

Se = 60 kpsi

and we know strength of friction f  = 0.82

and we take endurance limit Se is = 60 kpsi

so here coefficient value (a) will be

a = \frac{(f\times Su)^2}{Se}     ......................1  

put here value and we get

a = \frac{(0.82\times 120)^2}{60}  

a = 161.4  kpsi

so coefficient value (b) will be

b = -\frac{1}{3}log\frac{(f\times Su)}{Se}  

b =  -\frac{1}{3}log\frac{(0.82\times 120)}{60}  

b = −0.0716

so here number of cycle N will be  

N =  (\frac{ \sigma a}{a})^{1/b}

put here value  and we get

N =  (\frac{ 70}{161.4})^{1/-0.0716}

N = 117000

so life (N) of the specimen is 117000  cycles

7 0
3 years ago
A truck accelerates From being stopped to 18 m/s in 5.5 seconds. A bus accelerates from being stopped to 24 m/s in 6.0 seconds.
Mars2501 [29]

Answer:

The bus

Explanation:

a = (v-u)/t  

Where

a = acceleration

v = final velocity

u = initial velocity

t = time taken

For truck to get its acceleration,

a = (18-0)/5.5 = 3.27 ms⁻²

For bus to get its acceleration,

a = (24-0)/6 = 4 ms⁻²

As 4 > 3.27 bus has a greater acceleration.

5 0
3 years ago
The acceleration of the car with the data in the table above would be
neonofarm [45]

The acceleration of the car would be 0.33 first and then it would be 0.17.

<u>Explanation:</u>

An applied force is a force that is applied to an object by an individual or another item. On the off chance that an individual is pushing a work area over the room, at that point there is an applied power following up on the article. The applied power is the power applied on the work area by the individual.

The net force applied to the object rises to the mass of the article increased by the measure of its acceleration. The net power following up on the soccer ball is equivalent to the mass of the soccer ball duplicated by its adjustment in speed each second (its acceleration).

6 0
3 years ago
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