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gavmur [86]
3 years ago
9

What is the explicit formula for the sequence below? 4, -12, 36, -108 ...

Mathematics
2 answers:
liubo4ka [24]3 years ago
6 0

Answer:x ×-3

Step-by-step 4×-3= -12

-12 × -3= 36

and so on

Degger [83]3 years ago
4 0
Answer:
an = -6*(1/4)^(n-1)
Step-by-step explanation:
We have that the recursive formula for the given geometric sequence is:
a1 = -6
an = (an-1) * (1/4)
With the above we can assume that:
r = 1/4
following the rule of the explicit formula that is given by:
an = a1 * (r) ^ (n-1)
we substitute and we have:
an = -6 * (1/4) ^ (n-1)
Therefore the explicit formula from the given data would be:
an = -6 * (1/4) ^ (n-1)
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zavuch27 [327]
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6 0
3 years ago
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11. You plan to bake "apple crisp" for a dinner party you are hosting. Your recipe serves four
Ludmilka [50]

Answer:

2.5 teaspoon.

Step-by-step explanation:

4 serve recipe need cinnamon = 1 tsp

1 serve recipe need cinnamon = 1/4 tsp

10 serve recipe need cinnamon = 1/4 * 10

                                                      = 10/4

                                                      = 2.5 tsp

7 0
3 years ago
Which number line shows the solution set for |a|=6?
ivann1987 [24]

Answer:

the third one

Step-by-step explanation:

the absolute value of -6 is 6

3 0
2 years ago
For each of the following vector fields F , decide whether it is conservative or not by computing curl F . Type in a potential f
Phantasy [73]

The key idea is that, if a vector field is conservative, then it has curl 0. Equivalently, if the curl is not 0, then the field is not conservative. But if we find that the curl is 0, that on its own doesn't mean the field is conservative.

1.

\mathrm{curl}\vec F=\dfrac{\partial(5x+10y)}{\partial x}-\dfrac{\partial(-6x+5y)}{\partial y}=5-5=0

We want to find f such that \nabla f=\vec F. This means

\dfrac{\partial f}{\partial x}=-6x+5y\implies f(x,y)=-3x^2+5xy+g(y)

\dfrac{\partial f}{\partial y}=5x+10y=5x+\dfrac{\mathrm dg}{\mathrm dy}\implies\dfrac{\mathrm dg}{\mathrm dy}=10y\implies g(y)=5y^2+C

\implies\boxed{f(x,y)=-3x^2+5xy+5y^2+C}

so \vec F is conservative.

2.

\mathrm{curl}\vec F=\left(\dfrac{\partial(-2y)}{\partial z}-\dfrac{\partial(1)}{\partial y}\right)\vec\imath+\left(\dfrac{\partial(-3x)}{\partial z}-\dfrac{\partial(1)}{\partial z}\right)\vec\jmath+\left(\dfrac{\partial(-2y)}{\partial x}-\dfrac{\partial(-3x)}{\partial y}\right)\vec k=\vec0

Then

\dfrac{\partial f}{\partial x}=-3x\implies f(x,y,z)=-\dfrac32x^2+g(y,z)

\dfrac{\partial f}{\partial y}=-2y=\dfrac{\partial g}{\partial y}\implies g(y,z)=-y^2+h(y)

\dfrac{\partial f}{\partial z}=1=\dfrac{\mathrm dh}{\mathrm dz}\implies h(z)=z+C

\implies\boxed{f(x,y,z)=-\dfrac32x^2-y^2+z+C}

so \vec F is conservative.

3.

\mathrm{curl}\vec F=\dfrac{\partial(10y-3x\cos y)}{\partial x}-\dfrac{\partial(-\sin y)}{\partial y}=-3\cos y+\cos y=-2\cos y\neq0

so \vec F is not conservative.

4.

\mathrm{curl}\vec F=\left(\dfrac{\partial(5y^2)}{\partial z}-\dfrac{\partial(5z^2)}{\partial y}\right)\vec\imath+\left(\dfrac{\partial(-3x^2)}{\partial z}-\dfrac{\partial(5z^2)}{\partial x}\right)\vec\jmath+\left(\dfrac{\partial(5y^2)}{\partial x}-\dfrac{\partial(-3x^2)}{\partial y}\right)\vec k=\vec0

Then

\dfrac{\partial f}{\partial x}=-3x^2\implies f(x,y,z)=-x^3+g(y,z)

\dfrac{\partial f}{\partial y}=5y^2=\dfrac{\partial g}{\partial y}\implies g(y,z)=\dfrac53y^3+h(z)

\dfrac{\partial f}{\partial z}=5z^2=\dfrac{\mathrm dh}{\mathrm dz}\implies h(z)=\dfrac53z^3+C

\implies\boxed{f(x,y,z)=-x^3+\dfrac53y^3+\dfrac53z^3+C}

so \vec F is conservative.

4 0
3 years ago
A square rug has an inner square in the center. The side length of the inner square is x inches and the width of the outer regio
Gwar [14]

Answer: area of the outer part of the​ rug= 16 -x²

Step-by-step explanation:

Hi, to answer this question we have to apply the next formula:

Area of a square: Side²

Since the area of the rug including the inner square is:  

Area of the rug = 4² =16 in²

And the area of the inner square is equal to:

Area if the inner square = x²

To obtain the area of the outer part of the rug we have to subtract the area of the inner square to the area of the rug.

Area of the outer part of the rug= 16 -x²

Feel free to ask for more if needed or if you did not understand something.

6 0
2 years ago
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