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Evgen [1.6K]
3 years ago
5

Se aplica una fuerza de 8N a un cochecito de 650 gramos. Calcula: a) aceleración, b)espacio recorrido en 5 segundos y c) velocid

ad a los 3 segundos si parte del reposo
Physics
1 answer:
WITCHER [35]3 years ago
4 0

Respuesta:

a) 12.3 m/s²

b) 153.75 m

c) 36.9 m/s

Explicación:

Paso 1: Información provista

  • Fuerza aplicada (F): 8 N
  • Masa del cochecito (m): 650 g

Paso 2: Calcular la aceleración (a) del cochecito

Usaremos la segunda ley del movimiento de Newton.

F = m × a

a = F/m = 8 N / 0.650 kg = 12.3 m/s²

Paso 3: Calcular el espacio recorrido (x) en 5 segundos (t).

Usaremos la siguiente fórmula cinemática para un movimiento rectilineo uniformemente acelerado.

x = 1/2 × a × t²

x = 1/2 × 12.3 m/s² × (5s)² = 153.75 m

Paso 4: Calcular la velocidad (v) a los 3 segundos si parte del reposo

Usaremos la siguiente fórmula cinemática para un movimiento rectilineo uniformemente acelerado.

v = a × t

v = 12.3 m/s² × 3 s = 36.9 m/s

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Does the KE of a car change more when it accelerates from 22 km/h to 32 km/h or when it accelerates from 32 km/h to 42 km/h
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The change in kinetic energy (KE) of the car is more in the second case.

Explanation:

Let the mass of the car = m

initial velocity of the first case, u = 22 km/h = 6.11 m/s

final velocity of the first case, v = 32 km/h = 8.89 m/s

change in kinetic energy (K.E) = ¹/₂m(v² - u²)

                                          ΔK.E = ¹/₂m(8.89² - 6.11²)

                                                    = 20.85m J

 

initial velocity of the second case, u = 32 km/h = 8.89 m/s

final velocity of the second case, v = 42 km/h = 11.67 m/s

change in kinetic energy (K.E) = ¹/₂m(v² - u²)

                                          ΔK.E = ¹/₂m(11.67² - 8.89²)

                                                    = 28.58m J

The change in kinetic energy (KE) of the car is more in the second case.

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