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kipiarov [429]
3 years ago
13

How many significant digits are there in 11.090 mL? a. 5 b. 3 C. 1 d. 2

Physics
1 answer:
kati45 [8]3 years ago
5 0

Answer:

Five

Explanation:

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What does it mean when white light is diffracted and at a particular location the color seen is blue? Please use 2 content relat
Brilliant_brown [7]

When white light is diffracted and blue color is seen is due to the absorbance of wavelength of all other color except blue.

<u>Explanation: </u>

  • The white light diffracts into rainbow colors which are the 7 colors present in form of VIBGYOR.
  • VIBGYOR is the violet, Indigo, Blue, Green, Yellow, Orange and Red.
  • When the blue color is seen denotes the shortest wavelength being reflected and all other being absorbed at the specified location.

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3 years ago
What is the magnitude of the acceleration of a speck of clay on the edge of a potter's wheel turning at 45 rpm (revolutions per
Brilliant_brown [7]

Answer:

a_{cp}=7.77m/s^2

Explanation:

The equation for centripetal acceleration is a_{cp}=\frac{v^2}{r}.

We know the wheel turns at 45 rpm, which means 0.75 revolutions per second (dividing by 60), so our frequency is f=0.75Hz, which is the inverse of the period T.

Our velocity is the relation between the distance traveled and the time taken, so is the relation between the circumference C=2\pi r and the period T, then we have:

v=\frac{C}{T}=2\pi r f

Putting all together:

a_{cp}=\frac{(2\pi r f)^2}{r}=4 \pi^2f^2r=4 \pi^2(0.75Hz)^2(0.35m)=7.77m/s^2

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3 years ago
Hair sticking to a balloon after it<br> has been rubbed on a girl's head is<br> an example of
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Friction

Explanation:

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A test car starts from rest on a horizontal circular track of 115-m radius and increases its speed at a uniform rate to reach 90
Wewaii [24]

Answer:

a= 3.49 m/s^2

Explanation:

magnitude of total acceleration = sqrt{radial acceleration^2+tangential acceleration^2}.

we know that tangential acceleration a_t= change in velocity /time taken

now 90 km/h = 25 m/s

a_t = 25/17 = 1.47 m/s^2.

radial acceleration a_r = v^2/r

v= a_t×t = 1.47×13 = 19.11 m/s

a_r = 19.11^2/115=  3.175

now,

a= \sqrt{a_t^2+a_r^2}

a= \sqrt{1.47^2+3.175^2}

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