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kipiarov [429]
3 years ago
13

How many significant digits are there in 11.090 mL? a. 5 b. 3 C. 1 d. 2

Physics
1 answer:
kati45 [8]3 years ago
5 0

Answer:

Five

Explanation:

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According to Newton's Third Law, what is the equal and opposite force to the downward force of gravity pulling on a man standing
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The equal and opposite reaction to the gravitational force of the Earth pulling down on a man standing on the beach is the gravitational force of the man pulling up on the Earth. <em>(A)</em>

To put it in other words ... which should begin to blow your mind if you just take a moment to think about them ...

Your weight on Earth is exactly equal to the Earth's weight on YOU.

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3 years ago
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What will happen to the ball in example C if there is no friction?
Sloan [31]

Answer:

A) The ball will roll forever in a straight path.

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3 years ago
Five loops are formed of copper wire of the same gauge (cross-sectional area). Loops 1-4 are identical; Loop 5 has the same heig
nata0808 [166]
The answer to this question is A
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4 years ago
A 320-g ball and a 400-g ball are attached to the two ends of a string that goes over a pulley with a radius of 8.7 cm. Because
Gnom [1K]

To solve this problem, it is necessary to apply the concepts related to force described in Newton's second law, so that

F = ma

Where,

m = mass

a = Acceleration (Gravitational acceleration when there is action over the object of the earth)

Torque, as we know, is the force applied at a certain distance, that is,

\tau = F*d

Where

F= Force

d = Distance

Our values are given as,

m_1 = 0.32Kg

m_2 = 0.4Kg

d = 8.7*10^{-2}m

Since the system is in equilibrium the difference of the torques is the result of the total Torque applied, that is to say

\tau = T_2-T_1

\tau = F_2*d-F_1*d

\tau = m_2g*d-m_1*g*d

\tau = (m_2-m_1)g*d

\tau = (0.4-0.32)(9.8)(8.7*10^{-2})

\tau = 0.068N\cdot m

Therefore the magnitude of the frictional torque at the axle of the pulley if the system remains at rest when the balls are released is \tau = 0.068N\cdot m

8 0
3 years ago
Calculate the frequency (v) in Hertz (Hz) of a wave that has a wavelength of 4.71 meters.
MissTica

Answer:

6.37 x 10⁷Hz

Explanation:

Given parameters:

Wavelength = 4.71m

Unknown:

Frequency  = ?

Solution:

To solve this problem, we use the expression below:

           V = F∧  

V is the velocity  = 3 x 10⁸m/s

F is the frequency

∧ is the wavelength

  3 x 10⁸  = F x 4.71

      F  = 63694267.52Hz = 6.37 x 10⁷Hz

           

6 0
3 years ago
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