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3 years ago

Which term does not identify a vector quantity?

1 answer:

8 0

Here are a few:

-->  €
-->  £
-->  ¢
-->  ¥
-->  Ü
-->  Δ
-->  Σ
-->  Φ
-->  π
-->  Ω
-->  ω
-->  √
-->  ∞
-->  $
--> °C
--> °F

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Electrons are the right subatomic particle

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3 years ago

Help!! If an atom has 7 protons and 8 neutrons, and is not in an excited state, how many electrons would Bohr say the atom has?

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The answer I believe is 6

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3 years ago

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Dad gives the child on the sled a long push to set him in motion along the level surface

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3 years ago

A 49 kg person is being dragged in their sleeping bag to the lake by a 593 N

Alex777 [14]

Answer:

485.62 N

Explanation:

To obtain the magnitude of unbalanced forces acting on the body;

Unbalanced Force = Horizontal Component of Applied Force - Frictional Force

Frictional Force = Horizontal Component of Applied Force - Unbalanced Force

f = frictional force = ?

F = Applied force = 593 N

m = mass of person = 49 kg

a = acceleration = 0.57 m/s²

θ = Angle with horizontal = 30°

Hence;

Horizontal Component of Applied Force = (593 N)(Cos 30°)

Unbalanced Force = (49 kg)(0.57 m/s²)

f = (593 N)(Cos 30°) - (49 kg)(0.57 m/s²)

f = 513.55 N - 27.93 N

f = 485.62 N

6 0

3 years ago

Artificial gravity is a must for any space station if humans are to live there for any extended length of time. Without artifici

wariber [46]

Answer:

Hi myself Shrushtee.

Explanation:

Artificial gravity is a must for any space station if humans are to live there for any extended length of time. Without artificial gravity, human growth is stunted and biological functions break down. An effective way to create artificial gravity is through the use of a rotating enclosed cylinder, as shown in the figure. Humans walk on the inside edge of the cylinder, which is sufficiently large (diameter of 2235 meters) that its curvature is not readably noticeable to the inhabitants. (The space station in the figure is not drawn to the scale of the human.) Once the space station is rotating at the necessary speed, how many minutes would it take the space station to make one revolution?

The distance traveled by the man in one revolution is simply the circumference of the space station, C = 2p R. From this result, you should be able to deduce the time it takes for the space station to sweep out a complete revolution.

<h2>Please mark me as brainleist</h2>

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3 years ago