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blagie [28]
3 years ago
11

Robert is hosting a backyard barbecue. He uses a charcoal fire to grill the chicken. The chicken cooks, but it never touches the

fire directly. What energy transformation occurs as the chicken cooks?
Physics
2 answers:
Sveta_85 [38]3 years ago
8 0

Answer:

From chemical energy, to thermal energy. Which can be transfered via radiation or convection.

Explanation:

In our world, energy is constantly changing from one form, to another. The most basic law of physics is that energy cannot be created, nor destroyed, it can only change form.

This law allows us to do many calculations accurately.

In cooking, you have a source of energy, that heats up food, and then the food is cooked. In the question, there are a few energy convertions that take place.

The chemical energy stored in the coal is being released in the form of thermal energy.

When thermal energy is released, it can be transfered into the environment in three ways. Conduction, convection, and radiation.

Conduction is the transfer of thermal energy through two objects that are in direct contact with each other. However, since the question stated that the chicken doesn't directly touch the fire, conduction cannot occur.

Convection is the transfer of thermal energy, through a medium (usually air. In this example, the chicken is on a barbeque, so what happens is the charcoal transfers the thermal energy to the air around it, and when air heats up, it rises and transfers its energy to the environment as it rises (in this case, it would transfer a lot of that heat to the chicken).

Radiation is the transfer of thermal energy, without the need for a medium. We usually think of radiation as coming from the sun, and this is true because infrared waves are a form of radiation that can travel through space. Since the coal is producing radiation, it will travel until it comes into contact with something, this could be the chicken directly above it, or the people around the fire.

dimaraw [331]3 years ago
5 0

As the chicken cooks (and if it doesn't directly touch the fire), energy goes through the chemical, radiant, then thermal stages respectively.

The charcoal fire releases chemical energy. The heat of the fire is radiant, and the thermal (heat) of the fire cooks the chicken.

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Gate control theory of pain

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The energy needed to change an amount of a substance from a solid to a liquid is the
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Por una tubería de 0.06 m de diámetro circula agua con una velocidad desconocida, al llegar a la parte estrecha de la tubería de
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Answer:

La velocidad con la que se desplaza el agua antes de llegar a la parte estrecha de la tubería es 1.156 \frac{m}{s}

Explanation:

La ecuación de continuidad es simplemente una expresión matemática del principio de conservación de la masa.  Este principio establece que la masa de un objeto o colección de objetos nunca cambia con el tiempo.

La ecuación de continuidad es la relación que existe entre el área y la velocidad que tiene un fluido en un lugar determinado y dice que el caudal de un fluido es constante a lo largo de un circuito hidráulico.

En otras palabras, la ecuación de continuidad se basa en que el caudal (Q) del fluido ha de permanecer constante a lo largo de toda la conducción. Cuando un fluido fluye por un conducto de diámetro variable, su velocidad cambia debido a que la sección transversal varía de una sección del conducto a otra.

Entonces, siendo el caudal es el producto de la superficie de una sección del conducto por la velocidad con que fluye el fluido,  en dos puntos de una misma tubería se cumple:

Q1=Q2

A1*v1= A2*v2

donde:

  • A es la superficie de las secciones transversales de los puntos 1 y 2 del conducto.
  • v es la velocidad del flujo en los puntos 1 y 2 de la tubería.

Siendo A=pi*r^{2} =pi*(\frac{D}{2} )^{2} =\frac{pi*D^{2} }{4} , donde pi es el número π, r es el radio del conducto y D el diámetro del conducto, entonces:

\frac{pi*D1^{2} }{4}*v1=\frac{pi*D2^{2} }{4}*v2

En este caso:

  • D1: 0.06 m
  • v1: ?
  • D2: 0.04 m
  • v2: 2.6 m/s

Reemplazando:

\frac{pi*(0.06m)^{2} }{4}*v1=\frac{pi*(0.04m)^{2} }{4}*2.6\frac{m}{s}

Resolviendo:

v1=\frac{\frac{pi*(0.04m)^{2} }{4}*2.6\frac{m}{s}}{\frac{pi*(0.06m)^{2} }{4}}

v1=\frac{(0.04m)^{2} }{(0.06m)^{2}  }*2.6\frac{m}{s}

v1= 1.156 \frac{m}{s}

<u><em>La velocidad con la que se desplaza el agua antes de llegar a la parte estrecha de la tubería es 1.156 </em></u>\frac{m}{s}<u><em></em></u>

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