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3 years ago

What is the answer for O2 + C5H12O2 →?

Chemistry

1 answer:

ladessa [460]3 years ago

8 0

Answer:

25.76

Explanation:

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Which phase change requires more heat energy, Heat of fusion or Heat of

OverLord2011 [107]

Answer:

Evaporation involves a liquid becoming a gas and sublimation is the change of a solid directly to a gas. Phase changes require either the addition of heat energy (melting, evaporation, and sublimation) or subtraction of heat energy (condensation and freezing).

Explanation:

3 0

3 years ago

Read 2 more answers

While driving your rental car on your vacation in Europe, you find that you are getting 8.8 km/L of gasoline. What does this val

gizmo_the_mogwai [7]

Answer : The value correspond to in miles per gallon is, 20.6976 mile/gallon

Explanation :

The conversion used to convert kilometer to miles is:

1 km = 0.6214 miles

The conversion used to convert liter to gallon is:

1 L = 0.2642 gallons

Thus,

1 km/L = $\frac{0.6214}{0.2642}mile/gallon$

1 km/L = 2.352 mile/gallon

As we are given that 8.8 km/L of gasoline. Now we have to convert it into mile/gallon.

As, 1 km/L = 2.352 mile/gallon

So, 8.8 km/L = $\frac{8.8km/L}{1km/L}\times 2.352mile/gallon$

= 20.6976 mile/gallon

Thus, the value correspond to in miles per gallon is, 20.6976 mile/gallon

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3 years ago

The elements in Period 4 on the Periodic

lisov135 [29]

Atomic numbershould be correct

3 0

3 years ago

What pattern appears in the horizontal arrangement (rows) of the elements in the Periodic Table, moving from left to right?

Liula [17]

The horizontal rows in the periodic table are periods, while the vertical rows are called groups. The elements moving from left to right in "periods" have increasing atomic numbers.

5 0

3 years ago

The reaction 2CH4(g)⇌C2H2(g)+3H2(g) has an equilibrium constant of K = 0.154. If 6.30 mol of CH4, 4.20 mol of C2H2, and 11.15 mo

boyakko [2]

Answer:

C₂H₂ + 3H₂ ⟶ 2CH₄

Explanation:

The initial concentrations are:

[CH₄] = 6.30 ÷ 6.00 = 1.05 mol·L⁻¹

[C₂H₂] = 4.20 ÷ 6.00 = 0.700 mol·L⁻¹

[H₂] = 11.15 ÷ 6.00 = 1.858 mol·L⁻¹

2CH₄ ⇌ C₂H₂ + 3H₂

I/mol·L⁻¹: 1.05 0.700 1.858

$Q = \dfrac{\text{[C$_{2}$H$_{2}$][H$_{2}$]}^{3}}{\text{[CH$_{4}$]}^{2}} = \dfrac{ 0.700\times 1.858^{3}}{1.05^{2}}= 4.07$

Q > K

That means we have too many products.

The reaction will go to the left to get rid of the excess products.

C₂H₂ + 3H₂ ⟶ 2CH₄

8 0

4 years ago