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V125BC [204]
3 years ago
14

Consider the reaction: C2H5OH(ℓ) + 3O2(g) → 2CO2(g) + 3H2O(ℓ); ∆H = –1.37 x 103 kJ Consider the following statements: I. The rea

ction is endothermic II. The reaction is exothermic. III. The enthalpy term would be different if the water formed was gaseous. Which of these statement(s) is (are) true?
Chemistry
1 answer:
malfutka [58]3 years ago
4 0

Answer:

Two statements are true:

  • II. The reaction is exothermic.
  • III. The enthalpy term would be different if the water formed was gaseous.

Explanation:

  • C₂H₅OH(ℓ) + 3O₂(g) → 2CO₂(g) + 3H₂O(ℓ); ∆H = –1.37 × 10³ kJ

1. ∆H = –1.37 × 10³ kJ it telling that the enthalpy of the reaction is negative.

That means that reaction releases heat, which, by definition, means that the reaction is exothermic.

Then statement I is false and statement II is true.

2. The enthalpy of a reaction is equal to the enthalpy of the products less the enthalpy of the reactants:

       \Delta H_{rxn}=\sum (H_{products})-\sum (H_{reactants})

The enthalpy of each substance depends on its state, thus the enthalpy term for water will be different if it is formed as a gas than if it is formed a liquid.

Hence, the enthalpy of the reaction will be different in case the water formed was gaseous, and the third statement is also true.

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Rewrite the function from vertex form to standard form. Then use either form to calculate f(1) and f(-1).
jonny [76]

Answer:

Standard form: (x+3)^2=1/2(y+3)

f(1) = 29

f(-1) = 5

Explanation:

The standard form of a parabola with a directrix that is horizontal is

(x-h)=4(P)(y-k)

Using the vertex form, find the vertex, foci, and the distance from the vertex to the focus or directrix.

It's easier to use the vertex form to plug in values for x.

f(1) = 2((1)+3)^2-3

f(1) = 29

f(-1) = 2((-1)+3)^2-3

f(-1) = 5

6 0
4 years ago
All of the following can increase the rate of chemical reaction EXCEPT:
dangina [55]

Except catalyst because catalyst typically speed up a reaction by reducing the activation energy or changing the reaction mechanism.

5 0
3 years ago
Please help with question 4 and 5 please!!
ratelena [41]
Question four is : Gaseous state

Question five is : A rise in temperature increases the kinetic energy and speed of particles; it does not weaken the forces between them. The particles in solids vibrate about fixed positions; even at very low temperatures. Individual particles in liquids and gases have no fixed positions and move chaotically.

Hope this helps!

Have a great day!
8 0
3 years ago
Determine the molar mass of CuSO4 (the solute) in a 1.0M aqueous solution of CuSO4
inna [77]

Answer:

See explanation.

Explanation:

Hello,

In this case, we could have two possible solutions:

A) If you are asking for the molar mass, you should use the atomic mass of each element forming the compound, that is copper, sulfur and four times oxygen, so you can compute it as shown below:

M_{CuSO_4}=m_{Cu}+m_{S}+4*m_{O}=63.546 g/mol+32.00g/mol+4*16.00g/mol\\\\M_{CuSO_4}=159.546g/mol

That is the mass of copper (II) sulfate contained in 1 mol of substance.

B) On the other hand, if you need to compute the moles, forming a 1.0-M solution of copper (II) sulfate, you need the volume of the solution in litres as an additional data considering the formula of molarity:

M=\frac{n_{solute}}{V_{solution}}

So you can solve for the moles of the solute:

n_{solute}=M*V_{solution}

Nonetheless, we do not know the volume of the solution, so the moles of copper (II) sulfate could not be determined. Anyway, for an assumed volume of 1.5 L of solution, we could obtain:

n_{solute}=1mol/L*1.5L=1.5mol

But this is just a supposition.

Regards.

4 0
3 years ago
A barometer measures the pressure of the atmosphere at different altitudes. Identify the location where the column of mercury is
Ghella [55]
The location where the mercury level of the barometer would be the lowest is at the very high altitudes of the Earth's atmosphere (about 100 km), since air pressure decreases as altitude increases.
6 0
3 years ago
Read 2 more answers
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