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Allushta [10]
4 years ago
9

Mixtures have (exact,relative) amounts of the same substances

Chemistry
1 answer:
Ad libitum [116K]4 years ago
7 0

A heterogeneous mixture is one that is not evenly mixed

A homogeneous mixture is one that is evenly mixed

im pretty sure the answer you are looking for is relative though because mixtures do not have a fixed composition

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What is the ph of 0.175 m methylammonium bromide, ch3nh3br? (kb of ch3nh2 = 4.4 × 10−4.)?
KIM [24]
By using ICE table:

              CH3NH3+  +  H2O  → CH3NH4 2+   +  OH-

 initial       0.175                                   0                      0

change     -X                                     +X                     +X

Equ      (0.175-X)                                 X                      X

when: Ka = Kw / Kb 

     = (1 x 10^-14) / (4.4 x 10^-4) = 2.3 x 10^-11

when Ka = [CH3NH42+][OH-] / [CH3NH3+]

by substitution:

2.3 x 10^-11 = X^2 / (0.175 - X )    by solving for X

∴ X = 2 x 10^-6

∴[OH-] = 2 x 10^-6 

∴POH = -㏒[OH-]

           = -㏒(2 x 10^-6)

           = 5.7

when PH + POH = 14 

∴PH = 14 - 5.7 = 8.3
5 0
3 years ago
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Answer:

Concept: Chemical Analysis

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7 0
3 years ago
The metric system is also known as the
slega [8]

Answer:

THE answer is all of above

Explanation:

3 0
3 years ago
Read 2 more answers
What is the symbol for molarity?
Romashka-Z-Leto [24]

The answer in chemistry is mol/L and altho it is represented by the symbol M usually.

3 0
3 years ago
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A compound that is usually used as a fertilizer can also be used as a powerful explosive. the compound has the composition 35.00
maxonik [38]

Answer:

             Empirical Formula  =  NH₄NO₃ (Ammonium Nitrate)

Solution:

Step 1: Calculate Moles of each Element;

                      Moles of N  =  %N ÷ At.Mass of N

                      Moles of N  = 35.0 ÷ 14

                      Moles of N  =  2.5 mol


                      Moles of O  =  %O ÷ At.Mass of O

                      Moles of O  = 59.96 ÷ 16

                      Moles of O  =  3.7475 mol


                      Moles of H  =  [100% - (%N + %O)] ÷ At.Mass of H

                      Moles of H  = [100% - (35.0 + 59.96)] ÷ 1.008

                      Moles of H  = [100% - 94.96] ÷ 1.008

                      Moles of H  = 5.04 ÷ 1.008

                      Moles of H  =  5 mol

Step 2: Find out mole ratio and simplify it;

                N                                        H                                     O

               2.5                                       5                                3.7475

            2.5/2.5                                5/2.5                          3.7475/2.5

                 1                                         2                                     1.5

Multiply Mole Ratio by 2,

                 2                                         4                                     3

Result:

         Empirical Formula  =  N₂H₄O₃

Or,

         Empirical Formula  =  NH₄NO₃

This empirical formula is also a Molecular Formula for Ammonium Nitrate a well known Fertilizer and often misused in the formation of Explosives.

4 0
3 years ago
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