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Afina-wow [57]
3 years ago
14

Match the alkane names and structures. -butane -methane -ethane -propane

Chemistry
2 answers:
SpyIntel [72]3 years ago
7 0

Answer:

Explanation:

Here is the names and matches of butane methane ethane propane

gavmur [86]3 years ago
3 0
Butane goes to the second one

Methane goes to the third one

Ethane is the first one

Propane is the last one
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PLEASE CHECK MY ANSWERS AND VERIFY THEM! THANK YOU SO MUCH !!!!!
gregori [183]
You are correct! :) <3
5 0
3 years ago
A chef finds a sealed container consisting of an ingredient that goes into his restaurant's secret sauce. The ingredient's molec
LenaWriter [7]

Answer:

faster, and the ingredient will be a liquid.

Explanation:

7 0
3 years ago
Read 2 more answers
Which type of decay has the greatest mass?
iVinArrow [24]

The type of decay which has the greatest mass is the alpha decay. An unstable nucleus loses the most mass if the nucleus emits an alpha particle. This type of decay has the largest mass among the radioactive decay. When this particle is emitted from a nucleus, it loses two protons and two neutrons therefore large amount of mass is lost.

6 0
4 years ago
A molecule of ethyl alcohol is converted to acetaldehyde in one’s body by zero order kinetics. If the concentration of alcohol i
Oliga [24]

Answer:

(1) 0.0016 mol/L

Explanation:

Let the concentration of alcohol after 3.5 hours be y M

The reaction follows a first-order

Rate = ky^0 = change in concentration/time

k = 6.4×10^-5 mol/L.min

Initial concentration = 0.015 M

Concentration after 3.5 hours = y M

Time = 3.5 hours = 3.5×60 = 210 min

6.4×10^-5y^0 = 0.015-y/210

y^0 = 1

0.015-y = 6.4×10^-5 × 210

0.015-y = 0.01344

y = 0.015 - 0.01344 = 0.00156 = 0.0016 mol/L (to 4 decimal places)

5 0
3 years ago
How many grams of carbon dioxide (CO2) are produced from the combustion of 13.00 g of CH4?
boyakko [2]

Answer:

35.68g CO2

Explanation:

we use the combustion equation with CH4:

CH4+ O2= CO2 + H2O

And then balance it:

CH4+ 2O2= CO2 + 2H2O

Using this equation we can use sociometry:

13g CH4*\frac{1molCH4}{16.032gCH4} *\frac{1mol CO2}{1molCH4} *\frac{44g CO2}{1mol CO2}=35.68g CO2

We know that  16.032 is how many grams there are in one mole of CH4 by adding the weights of the atoms (12 +1.008+1.008+1.008+1.008). These weights can be found on the periodic table. The same goes for the amount of grams per CO2.

The important thing about sociometry is to make sure your units cancel out until you are only left with the unit you want. If grams of CH4 is in the numerator, the next fraction you multiply by should have grams of Ch4 in the denominator. If moles of CO2 are in the numerator, the next fraction should have moles of CO2 in the denominator.  

6 0
3 years ago
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