Answer:
The answer to your question is 0.036 M
Explanation:
Data
Molarity = ?
mass = 4.0 grams KOH
Volume = 2 L
Molecular mass KOH = 39 + 16 + 1 = 56 g
Formula
Process
1.- Calculate the moles of KOH using proportions
56 g of KOH ---------------- 1 mol
4 g of KOH ---------------- x
x = (4 x 1) / 56
x = 0.071 moles
2.- Substitute the values in the formula to find Molarity
3.- Simplification and result
Molarity = 0.036 M
Answer:
14 J of heat
Explanation:
Recall that the enthalpy of reaction is defined as the enthalpy change that occurs in a system when matter is transformed by a given chemical reaction, if all reactants and products are in their standard states. Here we have the heat of formation of six moles of the substance and we are expected to use it to obtain the the heat of formation of one mole of the compound and we can do that by simple proportion as shown below;
If 6 moles of the compound produces 84J of heat
1 mole of the substance will produce 1×84/6 = 14 J of heat
Answer:
I would say B
Explanation:
If I'm wrong I apologize, have a good day
For every question, you simply have to use the molar ratio method.
First find the mole of one substance using the formula, Moles=Mass/Mr.
Now compare them and find the moles of the substance whose mass you need using molar ratio. Use the formula written above to find the theoretical Mass required for reaction.