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zlopas [31]
3 years ago
8

Calculate the percent of composition of oxygen in Mercury (ll) oxide HgO

Chemistry
1 answer:
bekas [8.4K]3 years ago
6 0
Add up the molar mass of Mercury Oxide, and then divide the molar mass of Oxygen by the molar mass of the compound.

So...

mm of Hg + mm of O= 200.59g + 16g= 217g

16g/217g = .0737... x 100 = 7.37%
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Which piece of glassware shown below is used to hold and dispense a solution of known concentration during a titration?
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2 years ago
Number of grams of hydrogen than can be prepared from 6.80g of aluminum​
Anastaziya [24]

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0.7561 g.

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  • The hydrogen than can be prepared from Al according to the balanced equation:

<em>2Al + 6HCl → 2AlCl₃ + 3H₂,</em>

It is clear that 2.0 moles of Al react with 6.0 mole of HCl to produce 2.0 moles of AlCl₃ and 3.0 mole of H₂.

  • Firstly, we need to calculate the no. of moles of (6.8 g) of Al:

no. of moles of Al = mass/atomic mass = (6.8 g)/(26.98 g/mol) = 0.252 mol.

<em>Using cross multiplication:</em>

2.0 mol of Al produce → 3.0 mol of H₂, from stichiometry.

0.252 mol of Al need to react → ??? mol of H₂.

∴ the no. of moles of H₂ that can be prepared from 6.80 g of aluminum = (3.0 mol)(0.252 mol)/(2.0 mol) = 0.3781 mol.

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mass of H₂ = (no. of moles)(molar mass) = (0.3781 mol)(2.0 g/mol) = 0.7561 g.

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3 years ago
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