Parfocal is the term used to describe a microscope that maintains focus when the objective lenses are replaced.
<h3>
What is the name of the objective lens ?</h3>
For observing minute features within a specimen sample, a high-powered objective lens, often known as a "high dry" lens, is perfect. You can see a very detailed image of the specimen on your slide thanks to the 400x total magnification that a high-power objective lens and a 10x eyepiece provide.
The four objective lenses on your microscope are for scanning (4x), low (10x), high (40x), and oil immersion (100x).
The first-stage lens used to create a picture from electrons leaving the specimen is referred to as the "objective lens." The objective lens is the most crucial component of the imaging system since the quality of the images is determined by how well it performs (resolution, contrast, etc.,).
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X=r-p. Maybe I don't understand, but I am assuming that you need to isolate for X? you simply subtract p from both sides.<span />
The wavelength of the light ray with the given frequency is 4.05 × 10⁴nm.
Given the data in the question;
- Frequency of the light ray;
- Wavelength;
<h3>Wavelength</h3>
Wavelength can be simply defined as the spatial period of a periodic wave. When the shapes of waves are repeated, the distance over which they are repeated is called wavelength. Wavelength is expressed as;
Where 
is wavelength, f is frequency and c is speed of light( 
)
We substitute our values into the expression above to determine the wavelength of the light ray.
Therefore, the wavelength of the light ray with the given frequency is 4.05 × 10⁴nm.
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Answer:
correct answer is option 5 (The emission by the incident electron when it loses its energy in a single emission)
Explanation:
The emission by the incident electron when it loses its energy in a single emission then X-rays of minimum wavelength which is also known as X-rays of cut-off wavelength are emitted.
If potential V is applied on coolidge tube then cut-off wavelength of the continuous X-ray spectrum is related to the accelerating potential V by following equation
Angstrom/V
Answer:
Option B
Explanation:
This involves the conservation of momentum:
m1v1 = m2v2
Now initially neither the rock nor Bob is moving. Then the rock moves forward with a velocity of 5 m/s, having a mass of 20 kg. But Bob moves back by the conservation of momentum, so at what velocity?
0 = 20(5) + 100(vf),
-100 = 100vf,
vf = - 1m/s
