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3 years ago

The change in time for the first quarter is

Physics

2 answers:

krek1111 [17]3 years ago

5 0

Answer:

Calculate the change in time for each quarter of the track. Record the change in time in Table C of your Student Guide.

The change in time for the first quarter is

2.07

seconds.

The change in time for the second quarter is

1.09

seconds.

The change in time for the third quarter is

0.95

seconds.

The change in time for the fourth quarter is

0.81

seconds.

Explanation:

Im doing the virtual lab

Sholpan [36]3 years ago

3 0

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Which statements describe a physical property of matter? Check all that apply

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4 years ago

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Two facing surfaces of two large parallel conducting plates separated by 8.5 cm have uniform surface charge densities such that

elena-s [515]

Answer:

positive plate

E = 5.764 KV / m

W = 490eV or 7.85 * 10^-17 J

E_p = 4.74 *10^(-12) eV

E_k = 490 eV

Explanation:

part a

The potential difference between two plates = 490 V

Distance between two plates = 8.5 cm

Answer: The positive plate is at higher potential because of convention.

part b

Electric Field between the plates

E = V / d

E = 490 / 0.085 = 5.764 KV / m

Answer: Electric Field between the plates E = 5.764 KV / m

part c

Work done by electric field

W = V*q

W = 490 * 1.602*10^-19

W = 7.85 * 10^-17 J

or W = 490 eV

Answer: Work done by electric field W = 490eV or 7.85 * 10^-17 J

part d

Potential Energy of an electron gained:

E_p = m_e * g * d / (1.602*10^-19)

E_p = 9.109*10^-31* 9.81 * 0.085 / (1.602*10^-19)

E_p = 4.74 *10^(-12) eV

Very very small E_p approximately 0

Answer: Potential Energy of an electron gained E_p = 4.74 *10^(-12) eV or 0.

part e

Kinetic Energy of an electron gained:

W - E_p = E_k

E_k = 490eV - 4.74*10^(-12)eV

E_k = 490 eV

Answer: Kinetic Energy of an electron gained E_k = 490 eV

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4 years ago

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Answer:

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Explanation:

30 celsius = 86 fahrenheit

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3 years ago

A ball rolls 60 centimeters along a sidewalk in 5 seconds what is the speed of the ball.

meriva

Answer:

12 cm/s

Explanation:

Quite simply, you are looking for cm/s

so 60 cm / 5s = 12 cm/s

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2 years ago

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A 200 kg roller coaster is located at the top of a hill where the height is 30 m. What is the velocity when it reches the bottom

maw [93]

Assuming it starts at rest, the roller coaster only has potential energy at the top of the hill, which is

$E_P=(200\,\mathrm{kg})(30\,\mathrm m)g$

When it reaches the bottom, its potential energy will have converted to kinetic energy,

$E_K=\dfrac12(200\,\mathrm{kg})v^2$

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4 years ago

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