Answer:
Therefore the resistance of the air makes the movement not parabolic but shorter in each direction
Explanation:
The projectile motion is described by the kinematics equations giving a parabolic trajectory, where on the x axis there is no acceleration and on the y axis the acceleration is the acceleration of gravity.
When the air resistance is taken into account it can be approximated as a force that opposes the movement that for low speeds is proportional to the speed of the space.
Consequently, the movement in the axis and the acceleration is less, in some cases it can be so small that the constant handle speed, in this case, is called terminal velocity.
On the x-axis the friction force creates an acceleration in the negative direction of the movement that the projectile has to brake.
Therefore the resistance of the air makes the movement not parabolic but shorter in each direction.
Answer:
depends... do you add suger to your ketchup?
Explanation:
Answer:
The value is 
Explanation:
From the question we are told that
The velocity which the rover is suppose to land with is 
The mass of the rover and the parachute is 
The drag coefficient is 
The atmospheric density of Earth is 
The acceleration due to gravity in Mars is 
Generally the Mars atmosphere density is mathematically represented as
=> 
=> 
Generally the drag force on the rover and the parachute is mathematically represented as
=> 
=> 
Gnerally this drag force is mathematically represented as
Here A is the frontal area
So
=> 
=>
Answer:
13,750 N
Yes
Explanation:
Given:
v₀ = 90 km/h = 25 m/s
v = 0 m/s
t = 4 s
Find: a and Δx
a = Δv / Δt
a = (0 m/s − 25 m/s) / (4 s)
a = -6.25 m/s²
F = ma
F = (2200 kg) (-6.25 m/s²)
F = -13,750 N
Δx = ½ (v + v₀) t
Δx = ½ (0 m/s + 25 m/s) (4 s)
Δx = 50 m
Answer:
Explanation:
Let the volume of the unknown bulb = X L
The volume of the system , after opening valve = (X + 0.72 L )
Use Boyles law gas equation,
P1V1 = P2V2 ( at temperature is constant )
Given:
P1 = 1.2 atm
P2 = 683 torr
Converting mmHg to atm,
1 atm = 760 mmHg(torr)
683 mmHg = 683/760
= 0.8987 atm
1.2X = 0.8987*(X + 0.720)
1.2X = 0.8987X + 0.6471
0.3013X = 0.6471
X = 2.15 L
