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AlladinOne [14]
3 years ago
13

If you hold a permanent magnet the wrong way in an extremely strong magnetic f eld, its magnetization will be permanently revers

ed. What happens to the magnetic domains inside the permanent magnet during this process?
Physics
1 answer:
Phoenix [80]3 years ago
4 0

Answer: The domain that is aligned with the applied field will grow, while the domain that is oppositely aligned to the magnetic field will shrink, this is because permanent magnets produces their own magnetic field.

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Describe the difference between ‘conventional current’ and ‘electron flow’
Tamiku [17]

Answer:

Screenshot attached

Explanation:

6 0
3 years ago
The planet Uranus has a radius of 25,360 km and a surface acceleration due to gravity of 9.0 m/s^2 at its poles. Its moon Mirand
AlexFokin [52]

Answer:

8.67791\times 10^{25}\ kg

0.34589\ m/s^2

0.07903\ m/s^2

Explanation:

M = Mass of Uranus

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

r = Radius of Uranus = 25360 km

h = Altitude = 104000 km

r_m = Radius of Miranda = 236 km

m = Mass of Miranda = 6.6\times 10^{19}\ kg

Acceleration due to gravity is given by

g=\dfrac{GM}{r^2}\\\Rightarrow M=\dfrac{gr^2}{G}\\\Rightarrow M=\dfrac{9\times 25360000^2}{6.67\times 10^{-11}}\\\Rightarrow M=8.67791\times 10^{25}\ kg

The mass of Uranus is 8.67791\times 10^{25}\ kg

Acceleration is given by

a_m=\dfrac{GM}{(r+h)^2}\\\Rightarrow a_m=\dfrac{6.67\times 10^{-11}\times 8.67791\times 10^{25}}{(25360000+104000000)^2}\\\Rightarrow a_m=0.34589\ m/s^2

Miranda's acceleration due to its orbital motion about Uranus is 0.34589\ m/s^2

On Miranda

g_m=\dfrac{Gm}{r_m^2}\\\Rightarrow g_m=\dfrac{6.67\times 10^{-11}\times 6.6\times 10^{19}}{236000^2}\\\Rightarrow g_m=0.07903\ m/s^2

Acceleration due to Miranda's gravity at the surface of Miranda is 0.07903\ m/s^2

No, both the objects will fall towards Uranus. Also, they are not stationary.

6 0
3 years ago
A 4000-kg car bumps into a stationary 6000kg truck. The Velocity of the car before the collision was +4m/s and -1m/s after the c
Goryan [66]

Answer:

<em>The velocity of the truck is 3.33 m/s</em>

Explanation:

<u>Law Of Conservation Of Linear Momentum </u>

The total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and velocity v is  

P=mv.  

If we have a system of bodies, then the total momentum is the sum of the individual momentums:

P=m_1v_1+m_2v_2+...+m_nv_n

If some collision occurs, the velocities change to v' and the final momentum is:

P'=m_1v'_1+m_2v'_2+...+m_nv'_n

In a system of two masses:

m_1v_1+m_2v_2=m_1v'_1+m_2v'_2

There are two objects: The m1=4000 Kg car and the m2=6000 Kg truck. The car was moving initially at v1=4 m/s and the truck was at rest v2=0. After the collision, the car moves at v1'=-1 m/s. We need to find the velocity of the truck v2'. Solving for v2':

\displaystyle v'_2=\frac{m_1v_1+m_2v_2-m_1v'_1}{m_2}

Substituting:

\displaystyle v'_2=\frac{4000*4+6000*0-4000(-1)}{6000}

\displaystyle v'_2=\frac{16000+4000}{6000}

\displaystyle v'_2=3.33

The velocity of the truck is 3.33 m/s

7 0
3 years ago
What are the units for acceleration?
Anni [7]
The main units for acceleration are <span>the meter per squared second as told by Galileo Galilei. Although there can be more than one example, I consider this one to be correct. Hope it will help you in some measure.</span>
4 0
3 years ago
Pls tell the answer asap
Rzqust [24]
The maximum force acts between B and C as the graph is steepest showing maximum deceleration
5 0
3 years ago
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