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AlladinOne [14]
3 years ago
13

If you hold a permanent magnet the wrong way in an extremely strong magnetic f eld, its magnetization will be permanently revers

ed. What happens to the magnetic domains inside the permanent magnet during this process?
Physics
1 answer:
Phoenix [80]3 years ago
4 0

Answer: The domain that is aligned with the applied field will grow, while the domain that is oppositely aligned to the magnetic field will shrink, this is because permanent magnets produces their own magnetic field.

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During maneuvers preceding the Battle of Jutland, the British battle cruiser Lion moved as follows (in nautical miles): 1.2 mile
lana66690 [7]

Answer:

total distance is 11.3 miles

Explanation:

Given data:

distance to north = 1.2 miles

distance to south at 38 degree east of south = 6.1 miles  

distance to east of north at angle 89 degree = 4 miles  

distance to east of north at angle 31 degree =  6.5 miles

considering each displacement as vector so we have

\begin{pmatrix}0.0\\  1.2\end {pmatrix}   + \begin {pmatrix}3.8\\  -4.8\end{pmatrix} +\begin{pmatrix}4.0\\  0.1\end {pmatrix}+\begin{pmatrix}3.3\\  5.6\end{pmatrix} = \begin{pmatrix}11.1\\  2.1\end{pmatrix}

total distance is \sqrt{11.1^2 + 2.1^2} \approx  11.3

5 0
3 years ago
A force of 10 N causes a spring to extend by 20 mm. Find a) the spring constant of the spring in N/m b) the extension of the spr
suter [353]

(a) The spring constant is 500 N/m.

(b) The extension of the spring when 25 N force is applied is 0.05 m.

(c) The applied force to cause an extension of 5 mm is 2.5 N.

The given parameters:

  • Applied force, F = 10 N
  • Extension of the spring, x = 20 mm

The spring constant is calculated as follows;

F = kx\\\\k = \frac{F}{x} \\\\k = \frac{10}{20 \times 10^{-3}} \\\\k = 500 \ N/m

The extension of the spring when 25 N force is applied is calculated as follows;

F = kx\\\\x = \frac{F}{k} \\\\x = \frac{25}{500} \\\\x = 0.05 \ m

The applied force to cause an extension of 5 mm is calculated as follows;

F = kx\\\\F = 500 \times 5 \times 10^{-3}\\\\F = 2.5 \ N

Learn more about Hook's law here: brainly.com/question/12253978

7 0
3 years ago
When a board with a box on it is slowly tilted to larger and larger angle, common experience shows that the box will at some poi
eimsori [14]

Answer: The force of kinetic friction is smaller than that of static friction, but F_g  remains the same.

Explanation:

The situation is same as when a book is pushed with an increasing force on a table; When the force is low, book doesn't move, until that under a given force starts moving, and then it goes on movement even if the force decreases a bit.

The physical explanation for this, that friction force adopts any value needed to avoid to move the object, till a limit value is achieved, called static friction force, equal to the normal force times the static friction coefficient.

Once in movement, the kinetic friction coefficient replaces the static one , and  in general is lower than the static one, so the force diminishes.

In the case of the box sliding down the board, the force that tries to move the object down the board, is the component of the weight parallel to the board, that can be showed that being equal to the weight times the sinus of the angle of the board with the horizontal, as follows:

F_g = m g sin θ

When θ increases, F_g does the same, so friction force always has the same magnitude than F_g (but opposite direction) so the box doesn't move, till that θ takes a value that produces a F_g equal to static friction force.

Beyond this limit angle, F_g (remaining the same for a given angle) is greater than the kinetic friction force, and the box slides.

In the limit, when θ=90º, sin θ =1⇒ F_g = mg, so the object is in free fall.

6 0
4 years ago
_____ is the frictional force needed to slow an object in motion
s2008m [1.1K]

Answer:

<u>Drag force</u> is the frictional force needed to slow an object in motion

Explanation:

8 0
3 years ago
Read 2 more answers
An object completes one and half revolution of a circle of radius R calculate the displacement and distance
Papessa [141]

Answer:

Distance is path length covered by particle. When particle moves along half circle, it covers half the circumference therefore distance covered is (2×pi×r)/2 = pi× r. ... Hence displacement is equal to diameter or 2 times the radius of circle.

8 0
3 years ago
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