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dmitriy555 [2]
3 years ago
7

Predict the reactivity of beryllium compared with magnesium give a reason for your answer use the periodic table

Chemistry
1 answer:
Tanya [424]3 years ago
7 0

Answer:

Beryllium metal is relatively unreactive at room temperature, particularly in its massive form. Magnesium is more electropositive than the amphoteric beryllium and reacts more readily with most of the nonmetals.

Explanation:

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You know that an unlabeled bottle contains an aqueous solution of one of the following: AgNO3, KCl, or (NH4)2SO4. A friend sugge
Afina-wow [57]

Answer:

These tests determine the solubility of the compounds formed upon adding the test solution

Explanation:

Addition of Ba(NO₃)₂ will cause a precipitate ((Ba)₂SO₄) to form in the solution of (NH₄)₂SO₄. No precipitates will form in the other unknown solutions. Thus, whether or not the solution is ammonium sulfate can be determined.

Addition of NaCl solution will cause a precipitate (AgCl) to form in the solution of AgNO₃. No precipitates will form in the other unknown solutions. Thus, whether or not the solution is silver nitrate can be determined.

If no precipitates form, then the unknown solution must be KCl.

6 0
3 years ago
An aluminum can (Al) has a mass of 15.8 grams. How many atoms of aluminum are in the can?
Naddik [55]

Answer:

i think this is the answer you can try it tho...

Explanation:

Notice that the value 12.01 grams of natural carbon is the same as the atomic mass value (12.01 amu). It also tells us that 26.98 grams of aluminum contains exactly 6.022 x 1023 atoms of aluminum.

5 0
3 years ago
A geological sample is found to have a Pb-206/U-238 mass ratio of 0.337/1.00. Assuming there was no Pb-206 present when the samp
azamat

Answer:

Age=2.52*10^9 years

Explanation:

To determine the age, we need to know how much U have become Pb, so first we have to calculate the Pb moles present in a sample:

n_{Pb}=\frac{0.337g}{206g/mol}=0.00164 mol

n_{U}=\frac{1 g}{238g/mol}=0.0042 mol

The percentage of U degradation:

P=\frac{n_{Pb}}{n_{Pb}+n_{U}}

P=\frac{0.00164}{0.00164+0.0042}=0.28

Assuming that the life time is linear:

Age=\frac{4.5*10^9 years}{0.5 life time}*0.28 life time

Age=2.52*10^9 years

4 0
4 years ago
Read 2 more answers
Determine the concentration of a solution prepared by diluting 25.0 ml of a stock 0.188 m sr(no3)2 solution to 150.0 ml
o-na [289]
We can use the following equation to calculate the concentration of diluted solution.
c1v1 = c2v2 
where c1 is concentration and v1 is volume of stock solution, which is the more concentrated solution.
c2 is concentration and v2 is the volume of diluted solution.
substituting the values in the equation,
0.188 M x 25.0 mL = c2 x 150.0 mL 
c2 = 0.0313 M
concentration of diluted solution is 0.0313 M
8 0
3 years ago
In the ground state, has only 1 electron in a p orbital.
zepelin [54]
Aluminium is the element you are looking for
8 0
4 years ago
Read 2 more answers
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