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3 years ago

9

Use the bar graph to find the experimental probability of the event. Write your answer as a fraction or percent rounded to the n

earest tenth.

1 answer:

allsm [11]3 years ago

4 0

Do you still need the answer, because im working on the same question..

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The FBI wants to determine the effectiveness of their 10 Most Wanted list. To do so, they need to find out the fraction of peopl

Zinaida [17]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is X: number of criminals in the 10 Most Wanted list that were captured in a sample of 523 suspected criminals.

The number of criminals that were captured is 172 out of 523.

To calculate the sample proportion, you have to divide the number of success, in this case, captured criminals, by the total number of criminals sampled:

^p= 172/523= 0.329

I hope this helps!

7 0

4 years ago

Which value is NOT a solution of 8x3 – 1 = 0?

Tpy6a [65]

<u><em>Note: As you may have unintentionally missed to add the value choices. But, I would make sure to explain the concept so that you may improve your understanding in terms of solving these type of questions.</em></u>

Answer:

Any value other than the values $x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4}$ will not be a solution of $8x^3\:-\:1\:=\:0$ .

Step-by-step explanation:

Considering the equation

$8x^3\:-\:1\:=\:0$

Steps to solve the equation

$8x^3-1=0$

$\mathrm{Add\:}1\mathrm{\:to\:both\:sides}$

$8x^3-1+1=0+1$

$\mathrm{Simplify}$

$x^3=\frac{1}{8}$

$\mathrm{Divide\:both\:sides\:by\:}8$

$\frac{8x^3}{8}=\frac{1}{8}$

$\mathrm{Simplify}$

$x^3=\frac{1}{8}$

As

$\mathrm{For\:}x^3=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}$

$x=\sqrt[3]{\frac{1}{8}},\:x=\sqrt[3]{\frac{1}{8}}\frac{-1+\sqrt{3}i}{2},\:x=\sqrt[3]{\frac{1}{8}}\frac{-1-\sqrt{3}i}{2}$

So,

$x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4}$

Therefore,

Any value other than the values $x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4}$ will not be a solution of $8x^3\:-\:1\:=\:0$ .

Keywords: solution, value

Learn more about equation solution from brainly.com/question/1679491

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7 0

3 years ago

Help!! this is due Friday and I forgot how to do math

Hatshy [7]

I pretty sure it is A I looked it up.

5 0

3 years ago

Read 2 more answers

Factor 2pq - 5qr + 10r - 4p.

Tresset [83]

The answer is B) <span>(q - 2)(2p - 5r)

</span>2pq - 5qr + 10r - 4p = 2pq - 4p - 5qr + 10r
= 2pq - 4p - (5qr - 10r)
= 2p(q - 2) - 5r(q - 2)
= (q - 2)(2p - 5r)

5 0

3 years ago

"A day care program has an average daily expense of $75.00. The standard deviation is $5.00. The owner takes a sample of 64 bill

kolbaska11 [484]

Answer:

p=1

Step-by-step explanation:

Given that a day care program has an average daily expense of $75.00. The standard deviation is $5.00.

Sample size = 64

Std error of sample = $\frac{5}{\sqrt{64} } \\=0.625$

Thus sample mean will follow normal with

(75, 0.625)

Required probability

= $P(70$

It is almost a certain event with p =1

8 0

3 years ago

Read 2 more answers