The question is incomplete. The complete question is stated below:
Two point charges are held at the corners of a rectangle as shown in the figure. The lengths of sides of the rectangle are 0.050 m and 0.150 m. Assume that the electric potential is defined to be zero at infinity.
a. Determine the electric potential at corner A.
b. What is the electric potential energy of a +3 µC charge placed at corner A?
Answer / Explanation:
a )V(A) = 1 / 4πe° ( - 5 5x10∧6C / 0.150m + 2x10∧6C / 0.050m )
The answer to the equation above is : = +6.0x10∧4 j/c
b) U(A) = qV(A)= (3.0x10∧6C) (6.0x10∧4 . j/c) =
The answer to the equation above is : =0.18 J
Explanation:
Where V(A) is equivalent to the electric potential
U(A) is equivalent to the electric potential energy
Answer:
When aqueous solutions of silver(I) acetate and manganese(II) iodide are combined, an insoluble precipitate of silver(I) iodide is formed
Explanation:
- It is an example of precipitation reaction.
- When aqueous solutions of silver(I) acetate and manganese(II) iodide are combined, an insoluble precipitate of silver(I) iodide is formed.
- Precipitation of silver(I) iodide is confirmed by it's yellow color.
- Hence a reaction is observed.
- Molecular reaction:

Acid + base ------> salt + water
Answer:
2.01 A
Explanation:
Para esta pregunta debemos empezar por la semi-reaccion del plomo:

Se intercambian dos electrones en la semi-reacción del plomo. Si tenemos en cuenta la ecuación:

Donde:
<u>n= Moles depositados </u>
<u>I= Intensidad de corriente (en Amperios)</u>
<u>z= Numero de electrones intercambiados</u>
<u>F= Constante de faraday = 96484 C/mol</u>
<u>t=tiempo (en segundos)</u>
Que conocemos de esta ecuación?
<u>Los moles (se pueden calcular a partir de la masa atómica del plomo, 207.2 g/mol)</u>

<u>El tiempo (hay que convertirlo a segundos):</u>

<u>Z (Numero de electrones)</u>
De acuerdo a la semi-reacción son intercambiados 2 electrones.
<u>Por lo tanto podemos resolver para "I":</u>

Espero que sea de ayuda!
Hydrochloric acid is created