Answer:
Percentage of Ba = 52.5%
Explanation:
We'll begin by calculating the molar mass of Ba(NO3)₂. This can be obtained as follow:
Molar mass of Ba(NO3)₂ = 137 + 2[14 +(16×3)]
= 137 + 2[14 + 48]
= 137 + 2[62]
= 137 + 124
= 261 g/mol
Next, we shall determine the mass of Ba in Ba(NO3)₂. This can be obtained as follow:
Mass of Ba in Ba(NO3)₂ = 137 g/mol
Finally, we shall determine the percentage of Ba in Ba(NO3)₂. This can be obtained as follow:
Percentage of Ba = mass of Ba / mass of Ba(NO3)₂ × 100
Percentage of Ba = 137 / 261 × 100
Percentage of Ba = 13700 / 261
Percentage of Ba = 52.5%
Thus, the percentage of Ba in Ba(NO3)₂ is 52.5%
An ion with fewer electrons than its neutral atom is called a(n) cation. The charge of an ion with more electrons than its neutral atom is. negative.
Answer:
Step 1: Identify the Equation of Interest · Step 2: Determine the Potential Difference Across the Field · Step 3: Solve for the Speed
Explanation:
The combustion of methane, CH4, releases 890.4 kJ/mol. That is, when one mole of methane is burned, 890.4 kJ are given off to the surroundings. This means that the products have 890.4 kJ less than the reactants.
Answer:
the answer is 0 amu I hope it helps