1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Marianna [84]
4 years ago
10

A veterinarian's office recorded one particular week that they had 50 patients. The following table shows the recorded number of

dogs.
Monday Tuesday Wednesday Thursday Friday

7 4 5 5 2


The formula for standard error is given below, where represents the sample proportion, and n is the total number of elements in the sample.




Use the given data to complete the table below.


Percentage of patients that were dogs [23%; 42%; 22%; 46%]

Standard error [.07; .09; .05; .16]

Margin of error 90% confidence interval [(32%, 60%)(34%,58%)(6%, 23%)(5%,21%)]

Margin of error 95% confidence interval [(32%, 60%)(34%,58%)(6%, 23%)(5%,21%)]

Mathematics
1 answer:
Gre4nikov [31]4 years ago
3 0

Answer:

1. <u>The correct answer is 46%</u>

2. <u>The correct answer is .07</u>

<u>3. The correct answer is (34%,58%)</u>

4. <u>The correct answer is (32%,60%)</u>

Step-by-step explanation:

1. Let's calculate the percentage or proportion of patients that were dogs:

p = (7 + 4 + 5 + 5 + 2)/50 = 23/50 = 0.46

<u>The correct answer is 46%</u>

2. Let's estimate the standard error, using the given formula, this way:

S.e = √ (0.46 * 0.54)/50 = √0.049 = 0.07

<u>The correct answer is .07</u>

<u>3. </u>Let's calculate the confidence limits of the 90% confidence interval, this way:

Confidence limits = proportion +/- 1.645 * standard error

Confidence limits = 0.46 +/- 1.645 * 0.07

Confidence limits = 0.46 +/- 0.12

Confidence limits = 0.34, 0.58

<u>The correct answer is (34%,58%)</u>

4. <u> </u>Let's calculate the confidence limits of the 95% confidence interval, this way:

Confidence limits = proportion +/- 1.96 * standard error

Confidence limits = 0.46 +/- 1.96 * 0.07

Confidence limits = 0.46 +/- 0.14

Confidence limits = 0.32, 0.60

<u>The correct answer is (32%,60%)</u>

You might be interested in
A company manager for a tire manufacturer is in charge of making sure there is the least amount of defective tires. If the tire
Anestetic [448]

Answer:

0.347% of the total tires will be rejected as underweight.

Step-by-step explanation:

For a standard normal distribution, (with mean 0 and standard deviation 1), the lower and upper quartiles are located at -0.67448 and +0.67448 respectively. Thus the interquartile range (IQR) is 1.34896.

And the manager decides to reject a tire as underweight if it falls more than 1.5 interquartile ranges below the lower quartile of the specified shipment of tires.

1.5 of the Interquartile range = 1.5 × 1.34896 = 2.02344

1.5 of the interquartile range below the lower quartile = (lower quartile) - (1.5 of Interquartile range) = -0.67448 - 2.02344 = -2.69792

The proportion of tires that will fall 1.5 of the interquartile range below the lower quartile = P(x < -2.69792) ≈ P(x < -2.70)

Using data from the normal distribution table

P(x < -2.70) = 0.00347 = 0.347% of the total tires will be rejected as underweight

Hope this Helps!!!

6 0
3 years ago
Use the diagram and given information to answer the questions and prove the statement.
Greeley [361]

Answer:

See explanation

Step-by-step explanation:

<u> ASA Postulate (Angle-Side-Angle):</u>

If two angles and the included side of one triangle are congruent to the corresponding parts of another triangle, then the triangles are congruent.

Consider triangles XYB and ZYA. In these triangles

  • ∠X≅∠Z (given)
  • XY≅ZY (given)
  • ∠Y is common angle

By ASA Postulate, triangles XYB and ZYA are congruent. Congruent triangles have congruent corresponding sides, so

BX≅AZ

6 0
3 years ago
What is the vertex of Y equals X to the second power -4x-5​
Fed [463]

Answer:

vertex = (2, - 9 )

Step-by-step explanation:

Given a quadratic in standard form : ax² + bx + c : a ≠ 0

Then the x- coordinate of the vertex is

x_{vertex} = - \frac{b}{2a}

x² - 4x - 5 ← is in standard form

with a = 1, b = - 4, thus

x_{vertex} = - \frac{-4}{2} = 2

Substitute this value into the quadratic for corresponding value of y

(2)² - 4(2) - 5 = 4 - 8 - 5 = - 9

vertex = (2, - 9 )

5 0
3 years ago
86 is the same as u multiplied by 206
Gala2k [10]
U would equal 206/86 or 2.39585
6 0
3 years ago
What are the dimensions of the product?
Oksi-84 [34.3K]

Answer:

<h2>2 x 2</h2>

Step-by-step explanation:

Dimensions: m x n

m = number of rows

n = number of columns

When multiplying two matrices:

m x n *  n x k = m x k

MATIX 1:

m = number of rows

n = number of columns

MATRIX 2:

n = number of rows

k = number of columns

RESULTING MATIX:

m = number of rows

k = number of columns

2 x 3 * 3 x 2 = 2 x 2

8 0
3 years ago
Read 2 more answers
Other questions:
  • A man 6.2 ft tall casts a 8 ft shadow. How tall is a child that casts a 5.6 ft shadow at the same time of the day? (to the neare
    13·2 answers
  • Solve each given equation and show your work. Tell whether each equation has one solution, an infinite number of solutions, or n
    8·1 answer
  • Write a problem that can be solved by using equal groups
    11·1 answer
  • Delia has 3 5/8 yards of ribbon About how many 1/4 yard-long pieces can she cut
    5·1 answer
  • Can someone please help me
    5·1 answer
  • Item 1 A discounted concert ticket costs $14.50 less than the original price p . You pay $53 for a discounted ticket. Write an e
    14·1 answer
  • What advantages does money have over bartered goods? Check all that apply.
    11·2 answers
  • A small town is electing a new town council member. They decide to poll three random samples of registered voters to get an idea
    8·1 answer
  • Janie and Jasmine are playing three games at an arcade. Each of the games requires either 2, 3, or 4 tokens. The girls plan to p
    14·1 answer
  • There are 12 months in a year.
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!