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WITCHER [35]
2 years ago
10

A lumber company is making boards that are 2578.0 millimeters tall. If the boards are too long they must be trimmed, and if they

are too short they cannot be used. A sample of 20 boards is made, and it is found that they have a mean of 2580.2 millimeters with a variance of 64.00. Is there evidence at the 0.1 level that the boards are either too long or too short?
1. State the hypotheses.
2. Find the value of the t test statistic.
3. Specify if the test is one-tailed or two-tailed.
4. Determine the decision rule.
5. Determine the conclusion.
A) Reject Null Hypothesis
B) Fail to Reject Null Hypothesis
Mathematics
1 answer:
Tju [1.3M]2 years ago
6 0

Answer:

-0.750

Step-by-step explanation:

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Questão 02 - Carlos e sua mãe têm juntos atualmente 47 anos. Sabendo que sua mãe ganhou Carlos aos 23 anos, a equação que repres
mariarad [96]

Answer:

x+23 = 47

Step-by-step explanation:

Let age of Carlos is x. It is mentioned that the sum of age of Carlos and his mother is 47 years old. Age of Carlos is 23.

We need to find the equation that represents the sum of Carlos' age with his mother.

x+23 = 47 is the required equation.

Also, we can find the age of Carlos as :

x = 47 - 23

= 24 years

Hence, the correct option is (B).

8 0
2 years ago
For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains
AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

f(x) = (1-p)^{x}p

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

\mu = \frac{1-p}{p}

The standard deviation of the geometric distribution is given by the following formula:

\sigma = \sqrt{\frac{1-p}{p^{2}}

In this problem, we have that:

p = 0.383

So

\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61

\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05

(a) What is the probability that a drought lasts exactly 3 intervals?

This is f(3)

f(x) = (1-p)^{x}p

f(3) = (1-0.383)^{3}*(0.383)

f(3) = 0.09

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is P = f(0) + f(1) + f(2) + f(3)

f(x) = (1-p)^{x}p

f(0) = (1-0.383)^{0}*(0.383) = 0.383

f(1) = (1-0.383)^{1}*(0.383) = 0.236

f(2) = (1-0.383)^{2}*(0.383) = 0.146

Previously in this exercise, we found that f(3) = 0.09

So

P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4).

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

P(X \leq 3) + P(X \geq 4) = 1

0.855 + P(X \geq 4) = 1

P(X \geq 4) = 0.145

There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

8 0
3 years ago
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