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Alexxandr [17]
3 years ago
11

Read the excerpt from " Crossing the Brooklyn Ferry." Flood-tide below me! I see you face to face! Clouds of the west – sun ther

e half an hour high – I see you also face to face. Which statement best describes the effect of repeating the phrase "face to face"? It shows that the narrator sees the facial features of others. It demonstrates that the narrator is surrounded by nature. It demonstrates that the narrator is surrounded by people. It shows that the narrator is suspicious of the sea and sky.
Physics
2 answers:
Damm [24]3 years ago
8 0

Answer:

It demonstrates that the narrator is surrounded by nature.

Explanation:

Walt Whitman's "Crossing the Brooklyn Ferry" is a free verse poem written about the speaker's return trip on a ferry. He talks about his daily commute on the Brooklyn ferry, like the other commuters, and how they all share the same experience.

The given lines are from the very first stanza of the poem. The speaker repeats<em> "face-to-face" </em>when talking about nature. He sees the <em>"flood-tide below"</em> and the <em>"clouds"</em> high in the sky. This repetition demonstrates that he is surrounded by nature, amidst the throng of people around him. This shows the speaker's attitude of seeing the beauty of nature in any way he can, despite the bustle of commuting from Brooklyn to Manhattan.

Thus, the correct answer is the second option.

IRINA_888 [86]3 years ago
6 0

Answer:

b

Explanation:

the other guy is right

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A tin can has a radius of 0.0410m and is 185 m high if the air is removed from inside the can how much forces will the outside a
grin007 [14]

The force exerted on the bottle is 532 N

Explanation:

When the air is removed from inside the bottle, vacuum is created, therefore the external pressure (the atmospheric pressure) is no longer balanced, and it creates a net force downward on the can.

The pressure is related to the force by the equation:

p=\frac{F}{A}

where

p is the pressure

F is the force

A is the area of the can

Here we have:

p=1.01\cdot 10^5 Pa is the atmospheric pressure

r = 0.0410 m is the radius of the can, so the area is

A=\pi r^2 = \pi (0.0410)^2=5.27\cdot 10^{-3}m^2

And solving for F, we can find the force on the can:

F=pA=(1.01\cdot 10^5)(5.27\cdot 10^{-3})=532 N

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3 0
4 years ago
what is the acceleration produced by the resultant force acting on an object if the coefficient of friction acting between the b
LenKa [72]

The acceleration of the block is -0.98 m/s^2

Explanation:

The expression for the force of friction acting on the block is (assuming the surface is horizontal and flat):

F_f = -\mu mg

where

\mu is the coefficient of friction

m is the mass of the block

g is the acceleration of gravity

and where the negative sign means the direction of the force is opposite to that of the motion of the block

If this is the only force acting on the object, then this is also the resultant force, so we can rewrite Newton's second law as:

F=ma\\-\mu mg = ma

where

a is the acceleration of the block

Re-arranging the equation,

a=-\mu g

And so this is the expression for the acceleration of the block acted upon the force of friction.

In this problem, we have:

\mu=0.1

g=9.8 m/s^2

Solving,

a=-(0.1)(9.8)=-0.98 m/s^2

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5 0
4 years ago
Calculate the magnitude of the electric field at one corner of a square 2.42 m on a side if the other three corners are occupied
Karolina [17]

Ans:

12500 N/C

Explanation:

Side of square,  a = 2.42 m

q = 4.25 x 10^-6 C

The formula for the electric field is given by

E = \frac{Kq}{r^2}

where, K be the constant = 9 x 10^9 Nm^2/c^2 and r be the distance between the two charges

According to the diagram

BD = \sqrt{2}\times a

where, a be the side of the square

So, Electric field at B due to charge at A

E_{A}=\frac{Kq}{a^2}

E_{A}=\frac{9\times10^{9}\times 4.25 \times 10^{-6}}{2.42^2}

EA = 6531.32 N/C

Electric field at B due to charge at C

E_{C}=\frac{Kq}{a^2}

E_{C}=\frac{9\times10^{9}\times 4.25 \times 10^{-6}}{2.42^2}

Ec = 6531.32 N/C

Electric field at B due to charge at D

E_{D}=\frac{Kq}{2a^2}

E_{D}=\frac{9\times10^{9}\times 4.25 \times 10^{-6}}{2\times 2.42^2}

ED = 3265.66 N/C

Now resolve the components along X axis and Y axis

Ex = EA + ED Cos 45 = 6531.32 + 3265.66 x 0.707 = 8840.5 N/C

Ey = Ec + ED Sin 45 = 6531.32 + 3265.66 x 0.707 = 8840.5 N/C

The resultant electric field at B is given by

E=\sqrt{E_{x}^{2}+E_{y}^{2}}

E=\sqrt{8840.5^{2}+8840.5^{2}}

E = 12500 N/C

Explanation:

8 0
4 years ago
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Find the magnitude of the impulse delivered to a soccer ball when a player kicks it with a force of 1360 N. Assume that the play
Alona [7]

Answer:

7.59Ns

Explanation:

Given parameters:

Force  = 1360N

Time of contact  = 5.85 x 10⁻³s

Unknown:

Impulse  = ?

Solution:

The impulse of the ball is given as:

        Impulse  = Force x time

       Impulse  = 1360 x 5.85 x 10⁻³ = 7.59Ns

4 0
3 years ago
The material through which a mechanical wave travels is a.a medium.b.empty space.c.ether.d.air
Elza [17]
<h2>Answer: Medium </h2>

The medium is the main factor that differentiates a mechanical wave from an electromagnetic wave, since the first can not propagate without its existence, while the second can propagate regardless of whether the medium exists or not.

In addition, it is the medium that will define, the propagation speed of the wave, according to its specific physical characteristics.

Therefore, the <u>correct answer</u> is a.

5 0
3 years ago
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